x - 32457 x2 = 102478
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29 tháng 3 2023
955/5=191
5428:2=2714
32457:2=16228 dư 1
52645/4=13161 dư 1
82672:6=13778 dư 4
NV
0
4 tháng 1 2022
a: \(=\dfrac{x^2+3x+2-x^2+2x+8}{\left(x-2\right)\left(x+2\right)}=\dfrac{5x+10}{\left(x-2\right)\left(x+2\right)}=\dfrac{5}{x-2}\)
b: \(=\dfrac{x^2-4x+3-x^2-3x-2+8x}{\left(x-1\right)\left(x+1\right)}=\dfrac{x+1}{\left(x-1\right)\left(x+1\right)}=\dfrac{1}{x-1}\)
c: \(=\dfrac{x+2}{x\left(x-2\right)}+\dfrac{2}{x\left(x+2\right)}+\dfrac{3x+2}{\left(x+2\right)\left(x-2\right)}\)
\(=\dfrac{x^2+2x+2x-4+3x+2}{x\left(x-2\right)\left(x+2\right)}=\dfrac{x^2+7x-2}{x\left(x-2\right)\left(x+2\right)}\)
DT
4 tháng 1 2022
a,
\(\dfrac{x+1}{x-2}-\dfrac{x}{x+2}+\dfrac{8}{x^2-4}\\ =\dfrac{x^2+3x+2-x^2+2x+8}{\left(x-2\right)\left(x+2\right)}=\dfrac{5x+10}{\left(x-2\right)\left(x+2\right)}=\dfrac{5\left(x+2\right)}{\left(x-2\right)\left(x+2\right)}=\dfrac{5}{x-2}\)
b,
\(\dfrac{x-3}{x+1}-\dfrac{x+2}{x-1}+\dfrac{8x}{x^2-1}\\ =\dfrac{x^2-4x+3-x^2-3x-2+8x}{\left(x-1\right)\left(x+1\right)}=\dfrac{x+1}{\left(x-1\right)\left(x+1\right)}\\ =\dfrac{1}{x-1}\)
NH
1
23 tháng 7 2021
a) Ta có: \(x^2\left(x+1\right)+x+1=0\)
\(\Leftrightarrow\left(x+1\right)\left(x^2+1\right)=0\)
\(\Leftrightarrow x+1=0\)
hay x=-1
b) Ta có: \(x^2-x=-2x^2+2x\)
\(\Leftrightarrow3x^2-3x=0\)
\(\Leftrightarrow3x\left(x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)
c) Ta có: \(2x^2\left(x-1\right)+x^2=x\)
\(\Leftrightarrow2x^2\left(x-1\right)+x^2-x=0\)
\(\Leftrightarrow2x^2\left(x-1\right)+x\left(x-1\right)=0\)
\(\Leftrightarrow x\left(x-1\right)\cdot\left(2x+1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=1\\x=\dfrac{-1}{2}\end{matrix}\right.\)
d) Ta có: \(\left(x-2\right)\left(x^2+4\right)=x^2-2x\)
\(\Leftrightarrow\left(x-2\right)\left(x^2+4\right)-x\left(x-2\right)=0\)
\(\Leftrightarrow\left(x-2\right)\left(x^2-x+4\right)=0\)
\(\Leftrightarrow x-2=0\)
hay x=2
2 tháng 11 2021
\(b,=\left(x+8-x+2\right)^2=100\\ c,=x^2\left(x^2-16\right)-x^4+1=x^4-16x^2-x^4+1=1-16x^2\\ d,=x^3+1-x^3+1=2\)
2 tháng 11 2021
b) \(=\left(x+8-x+2\right)^2=10^2=100\)
c) \(=x^2\left(x^2-16\right)-\left(x^4-1\right)=x^4-16x^2-x^4+1=1-16x^2\)
d) \(=x^3+1-x^3+1=2\)
12345×2
\(x-\)64919=102478
\(x\) =102478+64919
\(x\) =167397