60 + 40 + x = 101
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
25 tháng 12 2021
a) 37.24+37.76+63.79+21.63
= 37(24+76)+63(79+21)
= 37.100+63.100
= (37+63)100
= 100.100
= 10000
b) 101+(-60)+29+(-40)
= (101+29)+(-60-40)
= 130-100
= 30
c) 40+(139-172+99)-(139+199-127)
= 40+139-172+99-139-199+127
= (139-139)+(-127+127)+(99-199)+40
= 0+0-100+40
= -60
d) (158.129-158.39):180
= [158(129-39)]:180
= (150.90):180
= 75
=
NK
3 tháng 1 2023
\(g,101+\left(-60\right)+29+\left(-40\right)=41+29+\left(-40\right)=70+\left(-40\right)=30\)
\(h,167+\left(-252\right)+52+\left(-67\right)=\left(-85\right)+52+\left(-67\right)=\left(-33\right)+\left(-67\right)=-100\)
\(i,38-138+250-350=\left(-100\right)+250-350=150-350=-200\)
\(k,118+107-\left(118-93\right)-50=225-25-50=100-50=50\)
\(m,40+\left(139-172+99\right)-\left(139+199-172\right)=40+\left[\left(-33\right)+99\right]-\left(338-172\right)\)
\(=40+66-166=106-166=-60\)
KT
5 tháng 2 2018
7) \(\frac{x+25}{75}+\frac{x+30}{70}=\frac{x+35}{65}+\frac{x+40}{60}\)
\(\Leftrightarrow\)\(\frac{x+25}{75}+1+\frac{x+30}{70}+1=\frac{x+36}{65}+1+\frac{x+40}{60}+1\)
\(\Leftrightarrow\)\(\frac{x+100}{75}+\frac{x+100}{70}=\frac{x+100}{65}+\frac{x+100}{60}\)
\(\Leftrightarrow\)\(\left(x+100\right)\left(\frac{1}{75}+\frac{1}{70}-\frac{1}{65}-\frac{1}{60}\right)=0\)
\(\Leftrightarrow\)\(x+100=0\) (vì 1/75 + 1/70 - 1/65 - 1/60 \(\ne\)0)
\(\Leftrightarrow\)\(x=-100\)
Vậy.....
KT
7 tháng 2 2018
7) \(\frac{x+25}{75}+\frac{x+30}{70}=\frac{x+35}{65}+\frac{x+40}{60}\)
\(\Leftrightarrow\)\(\frac{x+25}{75}+1+\frac{x+30}{70}+1=\frac{x+35}{65}+1+\frac{x+40}{60}+1\)
\(\Leftrightarrow\)\(\frac{x+100}{75}+\frac{x+100}{70}=\frac{x+100}{65}+\frac{x+100}{60}\)
\(\Leftrightarrow\)\(\left(x+100\right)\left(\frac{1}{75}+\frac{1}{70}-\frac{1}{65}-\frac{1}{60}\right)=0\)
\(\Leftrightarrow\)\(x+100=0\) (1/75 + 1/70 - 1/65 - 1/60 \(\ne\)0)
\(\Leftrightarrow\)\(x=-100\)
Vậy...
18 tháng 6 2022
9: \(\dfrac{x-49}{50}+\dfrac{x-50}{49}=\dfrac{49}{x-50}+\dfrac{50}{x-49}\)
=>x-99=0
hay x=99
7: \(\Leftrightarrow\left(\dfrac{x+25}{75}+1\right)+\left(\dfrac{x+30}{70}+1\right)=\left(\dfrac{x+35}{65}+1\right)+\left(\dfrac{x+40}{60}+1\right)\)
=>x+100=0
hay x=-100
8:
Sửa đề: \(\dfrac{99-x}{101}+\dfrac{97-x}{103}+\dfrac{95-x}{105}+\dfrac{93-x}{107}=-4\)
\(\Leftrightarrow\left(\dfrac{99-x}{101}+1\right)+\left(\dfrac{97-x}{103}+1\right)+\left(\dfrac{95-x}{105}+1\right)+\left(\dfrac{93-x}{107}+1\right)=0\)
=>200-x=0
hay x=200
100 + x = 101
x = 101 - 100
x = 1
60+40+x=101
100x = 101
x = 101-100
x= 1