Tính x: 55+66+x=0
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(45+75)*66+(75+45)*34
=(45+75)*(66+34)
=120*100
=12000
11+22+33+44+55+66+77+88+99:11
=11+22+33+44+55+66+77+88+9
=(11+9)+(22+88)+(33+77)+(44+66)+55
=20+110*3+55
=20+330+55
=405
Ta có :
a, (45 + 75) x 66 + (75 + 45) x 34
= (45 + 75) x (66 + 34)
= 120 x 100
= 12000
11 + 22 + 33 + 44 + 55 + 66 + 77 + 88 + 99 : 11
= 33 + 77 + 121 + 165 + 9
= 405
2*6=12
6*2=12
12:2=6
12:6=2
7*4=28
4*7=28
28:7=4
28:4=7
9*3=27
3*9=27
27:9=3
27:3=9
8*5=40
5*8=40
40:8=5
40:5=8
(12 + 77 + 34 + 23 + 88 + 45 + 55 + 66) x (45200 – 1808 x 25)
=(12 + 77 + 34 + 23 + 88 + 45 + 55 + 66) x (45200-45200)
=(12 + 77 + 34 + 23 + 88 + 45 + 55 + 66) x 0
=0
11x11=121
22x22=484
33x33=1089
44x44=1936
55x55=3025
66x66=4356
k mk nhé,1000000% đúng
\(=\left[66+34+77+23+12+88+45+55\right]\times\left[1808\times\left(25-25\right)\right]\\ =0\)
\(\dfrac{x-9}{55}+\dfrac{x-10}{66}=\dfrac{x-11}{77}+\dfrac{x-12}{88}\\ \Leftrightarrow\left(\dfrac{x-9}{55}+\dfrac{1}{11}\right)+\left(\dfrac{x-10}{66}+\dfrac{1}{11}\right)-\left(\dfrac{x-11}{77}+\dfrac{1}{11}\right)-\left(\dfrac{x-12}{88}+\dfrac{1}{11}\right)=0\)
\(\Leftrightarrow\left(\dfrac{x-9}{55}+\dfrac{5}{55}\right)+\left(\dfrac{x-10}{66}+\dfrac{6}{66}\right)-\left(\dfrac{x-11}{77}+\dfrac{7}{77}\right)-\left(\dfrac{x-12}{88}+\dfrac{8}{88}\right)=0\)
\(\Leftrightarrow\dfrac{x-4}{55}+\dfrac{x-4}{66}-\dfrac{x-4}{77}-\dfrac{x-4}{88}=0\)
\(\Leftrightarrow\left(x-4\right)\left(\dfrac{1}{55}+\dfrac{1}{66}-\dfrac{1}{77}-\dfrac{1}{88}\right)=0\\ \Leftrightarrow x=4\left(vì.\dfrac{1}{55}+\dfrac{1}{66}-\dfrac{1}{77}-\dfrac{1}{88}\ne0\right)\)
33 x 55 + 33 x 66 - 33 x 21
= 33 x ( 55 + 66 - 21 )
= 33 x 100
= 3300
a) \(\left|7x+3\right|=66\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}7x+3=66\\7x+3=-66\end{cases}}\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}7x=63\\7x=-69\end{cases}}\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x=9\left(N\right)\\x=-\frac{69}{7}\left(L\right)\end{cases}}\)
Vậy...
b) \(\left|5x-2\right|\le0\)
mà \(\left|5x-2\right|\ge0\)
\(\Rightarrow\)\(\left|5x-2\right|=0\)
\(\Leftrightarrow\)\(5x-2=0\)
\(\Leftrightarrow\)\(x=\frac{2}{5}\) (loại)
Vậy...
55+66+x=0
121+x=0
x=-121
#H
55+66+x=0
121+x=0
x=121