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NV
Nguyễn Việt Lâm
Giáo viên
12 tháng 11 2021
11c.
Từ đề bài ta có:
\(\left\{{}\begin{matrix}\dfrac{16a-b^2}{4a}=\dfrac{9}{2}\\16a+4b+4=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}2b^2=-4a\\b=-4a-1\end{matrix}\right.\)
\(\Rightarrow2b^2-b=1\Leftrightarrow2b^2-b-1=0\Rightarrow\left[{}\begin{matrix}b=1\Rightarrow a=-\dfrac{1}{2}\\b=-\dfrac{1}{2}\Rightarrow a=-\dfrac{1}{8}\end{matrix}\right.\)
Có 2 parabol thỏa mãn: \(\left[{}\begin{matrix}y=-\dfrac{1}{2}x^2+x+4\\y=-\dfrac{1}{8}x^2-\dfrac{1}{2}x+4\end{matrix}\right.\)
NV
Nguyễn Việt Lâm
Giáo viên
12 tháng 11 2021
4f.
Từ đề bài ta có:
\(\left\{{}\begin{matrix}1+b+c=0\\\dfrac{4c-b^2}{4}=-1\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}c=-b-1\\c=\dfrac{b^2}{4}-1\end{matrix}\right.\)
\(\Rightarrow\dfrac{b^2}{4}+b=0\)
\(\Rightarrow\left[{}\begin{matrix}b=0\Rightarrow c=-1\\b=-4\Rightarrow c=3\end{matrix}\right.\)
Có 2 parabol thỏa mãn: \(\left[{}\begin{matrix}y=x^2-1\\y=x^2-4x+3\end{matrix}\right.\)
DT
27 tháng 2 2022
4. achievements
5. competitive
6. climbing
7. player
8. famous
9. information
10. professional
11. competition
12. Congratulation
13. footballer
14. useful
15. loudly
DT
Đỗ Thanh Hải
CTVVIP
21 tháng 8 2021
1 not going on holiday with you
2 such easy questions that all the students got them right
3 we had had time, we would have visited the museum
4 to Daisy for breaking her vase
5 studying ENglish 5 years ago
6 are thought to be the most popular dance in Brazil
7 sooner had she received the exam result than she phoned her mom
8 It was the absence of leadership that caused most of the problems on the committee
9 you have any complants about the product, return it to the shop
10 The more fondness for the game increased , the more proficiency he has
11 been a dramatical rise in house prices this year
12 believed to have escaped in a stolen car
13 gone out with him for 2 years
14 he was going to meet his sister in front of the station
(D) bạn nhé mình ko nói dối ko tin có thể thử lại
d