Tìm x
0,3 x (x + 3/3 )=4:2/3
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\(a,A=\left(x^2-x\right)\left(x^2-x-12\right)\\ A=\left(x^2-x\right)^2-12\left(x^2-x\right)\\ A=\left(x^2-x\right)^2-12\left(x^2-x\right)+36-36\\ A=\left(x^2-x+6\right)^2-36\ge-36\\ A_{min}=-36\Leftrightarrow x^2-x+6=0\Leftrightarrow\left(x-3\right)\left(x+2\right)=0\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-2\end{matrix}\right.\\ b,B=4x^4+4x^3+5x^2+4x+3\\ B=\left(4x^4+4x^3+x^2\right)+\left(x^2+4x+4\right)-1\\ B=x^2\left(2x+1\right)^2+\left(x+2\right)^2-1\ge-1\\ B_{min}=-1\Leftrightarrow\left\{{}\begin{matrix}x\left(2x+1\right)=0\\x+2=0\end{matrix}\right.\Leftrightarrow x\in\varnothing\)
Vậy dấu \("="\) không xảy ra
\(a,\Leftrightarrow\left(2-x\right)\left(x^2+4\right)>0\Leftrightarrow2-x>0\Leftrightarrow x< 2\\ b,\Leftrightarrow x+3>0\Leftrightarrow x>-3\\ c,\Leftrightarrow\left[{}\begin{matrix}x< -3\\x>4\end{matrix}\right.\)
tham khảo nha;
https://loga.vn/hoi-dap/tim-biet-3-5-4-2-31679
# mui #
\(x+\dfrac{3}{4}=\dfrac{28}{6}+\dfrac{1}{2}\\ x+\dfrac{3}{4}=\dfrac{31}{6}\\ x=\dfrac{31}{6}-\dfrac{3}{4}\\ x=\dfrac{53}{12}\)
\(x+\dfrac{3}{4}=\dfrac{28+3}{6}=\dfrac{31}{6}\Leftrightarrow x=\dfrac{31}{6}-\dfrac{3}{4}=\dfrac{62-9}{12}=\dfrac{53}{12}\)
B=\(\frac{2002.\left(14+1\right)-1}{2001+2002.14}\)=\(\frac{2002.14+2001}{2001+2002.14}\)=1
Giải hộ mình câu này với:
(215/216+3971/3972-1/5)x(-9/35+2/5-1/7)=..........................?
X - (4,5 + 2,3) = 6,9
X - 6,8 = 6,9
X = 6,9 + 6,8
X = 13,7
\(\frac{5}{8}:x=\frac{1}{2}-\frac{1}{4}\)
\(\frac{5}{8}:x=\frac{1}{4}\)
\(x=\frac{5}{8}:\frac{1}{4}\)
\(x=\frac{5}{2}\)
\(\frac{1}{9}:\left(x-1\right)=\frac{1}{4}\)
\(\frac{1}{9}:x-\frac{1}{9}:1=\frac{1}{4}\)
\(\frac{1}{9}:x-\frac{1}{9}=\frac{1}{4}\)
\(\frac{1}{9}:x=\frac{1}{4}+\frac{1}{9}\)
\(\frac{1}{9}:x=\frac{13}{36}\)
\(x=\frac{13}{36}:\frac{1}{9}\)
\(x=\frac{13}{4}\)
X x 2 + X x 0,3 = 0,69
X x (2 + 0,3) = 0,69
X x 2,3 = 0,69
X = 0,69 : 2,3
X = 0,3
a) x - ( 4,5 + 2,3 )= 6,9
x - 6,8 = 6,9
x = 6,9 - 6,8
x = 0,1
b)\(\frac{5}{8}\): x = \(\frac{1}{2}-\frac{1}{4}\)
\(\frac{5}{8}-x=\frac{1}{4}\)
x = \(\frac{5}{8}-\frac{1}{4}\)
x = \(\frac{3}{8}\)
c) \(\frac{1}{9}:\left(x-1\right)=\frac{1}{4}\)
x - 1 = \(\frac{1}{9}:\frac{1}{4}\)
x - 1 = \(\frac{4}{9}\)
x = \(\frac{4}{9}+1\)
x = \(\frac{13}{9}\)
d) X x 2 + X x 0,3 = 0,69
X x ( 2 + 0,3 ) = 0,69
X x 2,3 = 0,69
X = 0,69 : 2,3
X = 0,3
\(A.\left(2a+1\right)^2-4\left(a+2\right)^2=9\\ \left(2a+1-2a-4\right)\left(2a+1+2a+4\right)=9\)
\(-3\left(4a+5\right)=9\\ -12a-15=9\\ -12a=24\\ a=-2\)
\(0,3\)x\(\left(x+\frac{3}{3}\right)=4:\frac{2}{3}\)
\(\Leftrightarrow0,3\)x\(\left(x+1\right)=6\)
\(\Leftrightarrow x+1=\frac{6}{0,3}\)
\(\Leftrightarrow x+1=20\)
\(\Leftrightarrow x=19\)
0,3 x ( X + 3/3 ) = 4 : 2/3 = 0,3 x ( X + 1 ) =6
x + 1 = 6 : 0,3
x + 1 = 20
x = 19