Rút gọn biểu thức:
a) \(\left(x^2-2x+2\right)\left(x^2-2\right)\left(x^2+2x+2\right)\left(x^2+2\right)\)
b) \(\left(a+b+c\right)^2+\left(a+b-c\right)^2+\left(2a-b\right)^2\)
c) \(100^2-99^2+98^2-97^2+...+2^2-1^2\)
d) \(3\left(2^2+1\right)\left(2^4+1\right)...\left(2^{64}+1\right)+1\)
Giup mình vs mình dang cần gấp
a) ( x2 - 2x + 2 )( x2 - 2 )( x2 + 2x + 2 )( x2 + 2 )
= [ ( x2 + 2 )2 - 4x2 ] ( x4 - 4 )
= ( x4 + 4 ) ( x4 - 4 )
= x8 - 16
b) ( a + b + c )2 + ( a + b - c )2 + ( 2a -b )2
= 2 ( a2 + b2 + c2 ) + 2 ( ab + bc + ac ) + 2 ( ab - bc - ac ) + ( 4a2 - 4ab + b2 )
= 2 ( a2 + b2 + c2 ) + 4ab - 4ab + 4a2 + b2
= 6a2 + 3b2 + 2c2
c) 1002 - 992 + 982 - 972 + ..... + 22 - 12
= ( 100 - 99 )( 100 + 99 ) + ( 98 - 97 )( 98 + 97 ) + ..... + ( 2 - 1 )( 2 + 1 )
= 199 + 197 + 195 + ..... + 5 + 3
= \(\frac{\left(199+3\right)\left(\left(199-3\right)\frac{1}{2}+1\right)}{2}\)
= 9999
d) 3 ( 22 + 1 )( 24 +1 )......( 264 + 1 ) + 1
= ( 22 -1 )( 22 + 1 )(24 + 1 ).....( 264 + 1 ) + 1
= ( 24 -1 )( 24 + 1 )( 28 + 1 )......( 264 + 1 ) +1
= ( 28 -1 )( 28 + 1).....( 264 + 1) +1
............
= ( 264 - 1)( 264 +1 ) + 1
= 2128