a)3x + x3 = 11 x 11
b)xx - 1x x 2 = 34
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a, 3x + x3 = 11x11
x+x+x+x+x+x = 121
6x = 121
x = 121 : 6
x = \(\frac{121}{6}\)
b, Xem lại đề đi .
Gọi m số là a,b,c => a+b=579, b+c=1245, c+a=912
a+b=579, b+c=1245 =>b+c-a-b=1245-579 => c-a=666
c+a=912, c-a=666 => c=789, a=123
b+c=1245, c=789 => b=456
\(\text{a) }\overline{3x}+\overline{x3}=11\times11\)
\(30+x+10x+3=121\)
\(11x=88\)
\(x=8\)
\(\text{b) }\overline{xx}-\overline{1x}\times2=34\)
\(10x+x-\left(10+x\right)\times2=34\)
\(10x+x-20-2x=34\)
\(9x=54\)
\(x=6\)
a) (2x+12x−1−2x−12x+1):4x10x−5=(2x+1)2−(2x−1)2(2x−1)(2x+1).10x+54x(2x+12x−1−2x−12x+1):4x10x−5=(2x+1)2−(2x−1)2(2x−1)(2x+1).10x+54x
=4x2+4x+1−4x2+4x−1(2x−1)(2x+1).5(2x+1)4x4x2+4x+1−4x2+4x−1(2x−1)(2x+1).5(2x+1)4x
=8x.5(2x+1)(2x−1)(2x+1).4x=102x−18x.5(2x+1)(2x−1)(2x+1).4x=102x−1
b) (1x2+x−2−xx+1):(1x+x−2)(1x2+x−2−xx+1):(1x+x−2)
=(1x(x+1)+x−2x+1):1+x2−2xx(1x(x+1)+x−2x+1):1+x2−2xx
=1+x(x−2)x(x+1).xx2−2x+11+x(x−2)x(x+1).xx2−2x+1
=(x2−2x+1)xx(x+1)(x2−2x+1)=1x+1(x2−2x+1)xx(x+1)(x2−2x+1)=1x+1
c) 1x−1−x3−xx2+1.(1x2−2x+1+11−x2)1x−1−x3−xx2+1.(1x2−2x+1+11−x2)
=1x−1−x3−xx2+1.[1(x−1)2−1(x−1)(x+1)]
a) (2x+12x−1−2x−12x+1):4x10x−5(2x+12x−1−2x−12x+1):4x10x−5
= 0 - 0
= 0
b) (1x2+x−2−xx+1):(1x+x−2);(1x2+x−2−xx+1):(1x+x−2)
= (x-xx+1) : (2x-2) : (x-xx+1) : (2x-2)
c) 1x−1−x3−xx2+1.(1x2−2x+1+11−x2)
= -2x-1-xx2+1. (14 - 4x)
= -x2-1-xx2+14-4x
= -6x-xx2+13
a.3x+x3=11.11
=>30+x+10x+x=11.11
=>33+11x=11.11
=>11(3+x)=11.11
=>3+x=11
=>x=8