1. Phân tích thành nhân tử:
xy(x + y) + yz(y + z) + xz(x+z) + 2xyz
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Những câu hỏi liên quan
LQ
1
PT
1
CM
7 tháng 10 2018
xy(x + y) + yz(y + z) + xz(x + z) + 2xyz
= x 2 y + x y 2 + yz(y + z) + x 2 z + x z 2 + xyz + xyz
= ( x 2 y + x 2 z) + yz(y + z) + (x y 2 + xyz) + (x z 2 + xyz)
= x 2 (y + z) + yz(y + z) + xy(y+ z) + xz(y + z)
= (y + z)( x 2 + yz + xy + xz) = (y + z)[( x 2 + xy) + (xz + yz)]
= (y + z)[x(x + y) + z(x + y)] = (y + z)(x+ y)(x + z)
KY
1
KP
2
23 tháng 7 2015
xy(x+y)+yz(y+z)+xz(x+z)+2xyz
= xy(x + y) + yz(y + z) + xyz + xz(x + z) + xyz
= xy(x + y) + yz(y + z + x) + xz(x + z + y)
= xy(x + y) + z(x + y + z)(y + x)
= (x + y)(xy + zx + zy + z2)
= (x + y)[x(y + z) + z(y + z)]
= (x + y)(y + z)(z + x)
23 tháng 7 2015
Ta co :
Đặt tổng trên là A
A= xy(x+y)+yz(y+z)+xz(x+z)+2xyz
A= xy(x + y) + yz(y + z) + xyz + xz(x + z) + xyz
A= xy(x + y) + yz(y + z + x) + xz(x + z + y)
A= xy(x + y) + z(x + y + z)(y + x)
A= (x + y)(xy + zx + zy + z2 )
A= (x + y)[x(y + z) + z(y + z)]
A= (x + y)(y + z)(z + x)
C
1
30 tháng 9 2015
xy(x+y)+yz(y+z)+xz(x+z)+2xyz
= xy(x + y) + yz(y + z) + xyz + xz(x + z) + xyz
= xy(x + y) + yz(y + z + x) + xz(x + z + y)
= xy(x + y) + z(x + y + z)(y + x)
= (x + y)(xy + zx + zy + z²)
= (x + y)[x(y + z) + z(y + z)]
= (x + y)(y + z)(z + x)
**** đi nak , làm rui đó
VT
2
28 tháng 9 2016
xy(x+y)+yz(y+z)+xz(x+z)+2xyz
= xy(x + y) + yz(y + z) + xyz + xz(x + z) + xyz
= xy(x + y) + yz(y + z + x) + xz(x + z + y)
= xy(x + y) + z(x + y + z)(y + x)
= (x + y)(xy + zx + zy + z2)
= (x + y)[x(y + z) + z(y + z)]
= (x + y)(y + z)(z + x)
28 tháng 9 2016
xy(x+y)+yz(y+z)+xz(x+z)+2xyz
= xy(x + y) + yz(y + z) + xyz + xz(x + z) + xyz
= xy(x + y) + yz(y + z + x) + xz(x + z + y)
= xy(x + y) + z(x + y + z)(y + x)
= (x + y)(xy + zx + zy + z²)
= (x + y)[x(y + z) + z(y + z)]
= (x + y)(y + z)(z + x)
GT
2
LT
1
NM
2
28 tháng 7 2016
xy(x+y)+yz(y+z)+xz(x+z)+2xyz
= xy(x + y) + yz(y + z) + xyz + xz(x + z) + xyz
= xy(x + y) + yz(y + z + x) + xz(x + z + y)
= xy(x + y) + z(x + y + z)(y + x)
= (x + y)(xy + zx + zy + z²)
= (x + y)[x(y + z) + z(y + z)]
= (x + y)(y + z)(z + x)
TN
28 tháng 7 2016
xy(x+y)+yz(y+z)+xz(x+z)+2xyz
= xy(x + y) + yz(y + z) + xyz + xz(x + z) + xyz
= xy(x + y) + yz(y + z + x) + xz(x + z + y)
= xy(x + y) + z(x + y + z)(y + x)
= (x + y)(xy + zx + zy + z²)
= (x + y)[x(y + z) + z(y + z)]
= (x + y)(y + z)(z + x)
\(xy\left(x+y\right)+yz\left(y+z\right)+xz\left(x+z\right)+2xyz.\)
\(=x^2y+xy^2+y^2z+yz^2+xz\left(x+z\right)+2xyz\)
\(=\left(x^2y+xyz\right)+\left(xy^2+y^2z\right)+\text{(}yz^2+xyz\text{)}+xz\left(x+z\right)\)
\(=xy\left(x+z\right)+y^2\left(x+z\right)+yz\left(x+z\right)+xz\left(x+z\right)\)
\(=\left(x+z\right)\left(xy+y^2+yz+xz\right)\)
\(=\left(x+z\right)\text{[}y\left(x+y\right)+z\left(x+y\right)\text{]}\)
\(=\left(x+z\right)\left(x+y\right)\left(y+z\right)\)