Tính nhanh :
a) 1012 ; b) 1992 ; c) 47.53
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a) 1012 = (100 + 1)2 = 1002 + 2.100 + 1 = 10000 + 200 + 1 = 10201
b) 1992 = (200 – 1)2 = 2002 – 2.200 + 1 = 40000 – 400 + 1 = 39601
c) 47.53 = (50 – 3)(50 + 3) = 502 – 32 = 2500 – 9 = 2491.
\(101^2=\left(100+1\right)^2=10000+200+1=10201\)
\(1001^2=\left(1000+1\right)^2=1000000+2000+1=1002001\)
\(102^2=\left(100+2\right)^2=10000+400+4=10404\)
\(99^2=\left(100-1\right)^2=10000-200+1=9801\)
\(19^2=\left(10+9\right)^2=100+180+81=361\)
\(999^2=\left(1000-1\right)^2=1000000-2000+1=998001\)
Ta có :
\(A=\frac{2012.14+1997+2010.2011}{2011.5+2011.1008+1012.2011}\)
\(\Rightarrow A=\frac{\left(2011+1\right).14+1997+2010.2011}{2011.\left(5+1008+1012\right)}\)
\(\Rightarrow A=\frac{2011.14+14+1997+2010.2011}{2011.2025}\)
\(\Rightarrow A=\frac{2011.14+2011+2010.2011}{2011.2025}\)
\(\Rightarrow A=\frac{2011.\left(14+1+2011\right)}{2011.2025}\)
\(\Rightarrow A=\frac{2011.25}{2011.25}\)
\(\Rightarrow A=1\) ( tử số = mẫu số )
Vậy \(A=1\)
~ Ủng hộ nhé
có lộn đề ko bn ơi
c). 1081.46
d). 1000
e. P=(x−y)(x2+xy+y2)−2y3=x3−y3−2y3=x3−3y3=(12)3−3.(23)3=−5572
a) = 117 x 100 - 17 x 100
= ( 117 - 17 ) x 100
= 100 x 100
= 10000
b) ( 532 x 7 - 266 x 14 ) x ( 532 x 7 + 266 )
= 532 x 7 - 266 x ( 2 x 7 ) x 3990
= 532 x 7 - 266 x 2 x 7 x 3990
= (532 x 7 - 532 x 7) x 3990
= 0 x 3990
= 0
c) 506 x 5 + 1012 + 253 x 6
= 506 x 5 + (506 x 2) + 253 x ( 2 x 3 )
= 506 x 5 + 506 x 2 + 253 x 2 x 3
= 506 x 5 + 506 x 2 + 506 x 3
= 506 x ( 5 + 2 + 3 )
= 506 x 10
= 5060
a) 1012 = (100+1)^2 = 100^2 + 200 + 1 = 10 000 + 200 +1 = 10 201
b) 1992 = (200 -1)^2 = 200^2 - 400 +1 = 40 000 - 400 +1 = 39 601
; c) 47.53 = (50-3) (50+3) = 50^2 - 3^2= 2500 -9 =2491
a) \(\left(100+1\right)^2=100^2+2\times100\times1+1^2=10000+200+1=10201\)
b)\(=\left(200-1\right)^2=200^2-2\times200\times1+1^2=40000-200+1=39801\)
c)\(=\left(50-3\right)\times\left(50+3\right)=50^2-3^2=2491\)