tìm x biết :
a) 3/4 - 3/4 : x = 1/2
b) -12 x ( x - 5 ) + 7 . ( 3 - x ) = 5
c) / 7x + 3 / = 66
d ) ( x - 7 ) . ( x +3 ) < 0
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a) \(\frac{3}{4}-\frac{3}{4}:x=\frac{1}{2}\)
\(\Leftrightarrow\frac{3}{4}:x=\frac{1}{4}\Leftrightarrow x=3\)
b) \(-12.\left(x-5\right)+7.\left(3-x\right)=5\)
\(\Leftrightarrow-12x+60+21-7x=5\Leftrightarrow-19x+81=5\Leftrightarrow-19x=-76\)
\(\Leftrightarrow x=4\)
c) \(\left|7x+3\right|=66\Leftrightarrow7x+3=66\text{ hoặc }-7x-3=66\)
\(\Leftrightarrow7x=63\text{ hoặc }-7x=69\)
\(\Leftrightarrow x=9\text{ hoặc }x=-\frac{69}{7}\)
d) \(\left(x-7\right).\left(x+3\right)< 0\Leftrightarrow x-7< 0\text{ và }x+3>0\Leftrightarrow x< 7\text{ và }x>-3\)
\(\Leftrightarrow-3< x< 7\)
a) 3/4-3/4:x=1/2
=>3/4:x=3/4-1/2
=>3/4:x=3/4-2/4
=>3/4:x=1/4
=>x=3/4:1/4
=>x=3/4.4/1
=>x=4
b)-12.(x-5)+7.(3-x)=5
=>-12x+60+21-7x=5
=>81-19x=5
=>19x=81-5
=>19x=76
=>x=76:19
=>x=4
c) |7x+3|=66
=>7x+3=-66 hoặc 7x+3=66
+)Nếu 7x+3=-66
=>7x=-66-3=-66+(-3)=-69
=>x=(-69):7=\(\frac{-69}{7}\)
+)Nếu 7x+3=66
=>7x=66-3=63
=>x=x=63:7=9
d)(x-7)(x+3)<0
=>x-7<0 hoặc x+3<0
+)/nếu x-7<0
=>x<7
+)nếu x+3<0
=>x<-3
a ) \(-5\times\left(-x+7\right)-3\times\left(-x-5\right)=-4\times\left(12-x\right)+48\)
\(\Leftrightarrow5x-35+3x+15=-48+4x+48\)
\(\Leftrightarrow5x-3x+4x=35-15-48+48\)
\(\Leftrightarrow2x=20\)
\(\Leftrightarrow x=10\)
b ) \(-2\times\left(15-3x\right)-4\times\left(-7x+8\right)=-5-9\times\left(-2x+1\right)\)
\(\Leftrightarrow-30+6x-28x-32=-5+18x-9\)
\(\Leftrightarrow6x-28x-18x=30+32-5-9\)
\(\Leftrightarrow-40x=48\)
\(\Leftrightarrow x=-1.2\)
Bài 1:
a) \(-5\left(x^2-3x+1\right)+x\left(1+5x\right)=x-2\)
\(\Rightarrow-5x^2+15x-5+x+5x^2=x-2\)
\(\Rightarrow16x-5=x-2\)
\(\Rightarrow16x-x=5-2\)
\(\Rightarrow15x=3\)
\(\Rightarrow x=\dfrac{15}{3}=5\)
b) \(12x^2-4x\left(3x+5\right)=10x-17\)
\(\Rightarrow12x^2-12x^2-20x=10x-17\)
\(\Rightarrow-20x=10x-17\)
\(\Rightarrow-20x-10x=-17\)
\(\Rightarrow-30x=-17\)
\(\Rightarrow x=\dfrac{-30}{-17}=\dfrac{30}{17}\)
c) \(-4x\left(x-5\right)+7x\left(x-4\right)-3x^2=12\)
\(\Rightarrow-4x^2+20x+7x^2-28x-3x^2=12\)
\(\Rightarrow-8x=12\)
\(\Rightarrow x=\dfrac{12}{-8}=-\dfrac{4}{3}\)
Bài 2:
a) \(\left(x+5\right)\left(x-7\right)-7x\left(x-3\right)\)
\(=x^2-7x+5x-35-7x^2+21x\)
\(=-6x^2+19x-35\)
b) \(x\left(x^2-x-2\right)-\left(x-5\right)\left(x+1\right)\)
\(=x^3-x^2-2x-x^2+x-5x-5\)
\(=x^3-2x^2-6x-5\)
c) \(\left(x-5\right)\left(x-7\right)-\left(x+4\right)\left(x-3\right)\)
\(=x^2-7x-5x+35-x^2-3x+4x-12\)
\(=11x+23\)
d) \(\left(x-1\right)\left(x-2\right)-\left(x+5\right)\left(x+2\right)\)
\(=x^2-2x-x+2-x^2+2x+5x+10\)
\(=4x+12\)
x(x+2)=0
suy ra x=0 hoặc x+2=0
5-2x=-7
2x=-7+5
2x=-(7-5)
2x=-2
x=-2:2
x=-1
Vậy x=-1
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\(a,\frac{3}{4}-\frac{3}{4}:x=\frac{1}{2}\)
\(\frac{3}{4}:x=\frac{3}{4}-\frac{1}{2}\)
\(\frac{3}{4}:x=\frac{1}{4}\)
\(x=\frac{3}{4}:\frac{1}{4}\)
\(x=3\)