\(\frac{8}{11}+\frac{8}{33}\)x\(\frac{3}{4}\)
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a) \(\frac{x}{3}\)\(-\)\(\frac{1}{8}\)\(=\)\(\frac{5}{8}\)
\(\Rightarrow\) \(\frac{x}{3}\)=\(\frac{5}{8}+\frac{1}{8}\)
\(\Rightarrow\) \(\frac{x}{3}\)\(=\frac{3}{4}\)
\(\Rightarrow\) x=3.3:4
\(\Rightarrow\) x=2,25
Vậy x=2,25
b) \(3\frac{1}{3}\).x-\(6\frac{3}{4}=3\frac{1}{4}\)
\(\Rightarrow\)\(\frac{10}{3}\).x-\(\frac{27}{4}=\frac{13}{4}\)
\(\Rightarrow\) \(\frac{10}{3}\).x=\(\frac{13}{4}+\frac{27}{4}\)
\(\Rightarrow\) \(\frac{10}{3}\).x=10
\(\Rightarrow\) x=\(10\div\frac{10}{3}\)
\(\Rightarrow\) x=3
Vậy x=3
Ủng hộ mik nha mọi người !
Ta có : \(\frac{x}{3}-\frac{1}{8}=\frac{5}{8}\)
\(\Leftrightarrow\frac{x}{3}=\frac{5}{8}-\frac{1}{8}\)
\(\Leftrightarrow\frac{x}{3}=\frac{1}{2}\)
\(\Leftrightarrow x=\frac{1}{2}.\frac{1}{3}=\frac{1}{6}\)
= 19/4 - 0,37 + 1/8 - 1,28 - 2,5 + 37/12
= 19/4 - 37/100 + 1/8 - 32/25 - 5/2 + 37/12
= 219/50 + (-231/200) - 67/12
= 129/40 - 67/12
=(-283/120)
bạn k cho mình đi làm ơn đó
\(4\frac{3}{4}-0,37+\frac{1}{8}-1,28-2,5+3\frac{1}{12}\)
\(=\frac{19}{4}-\frac{37}{100}+\frac{1}{8}-\frac{32}{25}-\frac{5}{2}+\frac{37}{12}\)
\(=\frac{4750}{1000}-\frac{370}{1000}+\frac{125}{1000}-\frac{1280}{1000}-\frac{2500}{1000}+\frac{37}{12}\)
\(=\frac{4750-370+125-1280-2500}{1000}+\frac{37}{12}\)
\(=\frac{29}{40}+\frac{37}{12}=\frac{87}{120}+\frac{370}{120}=\frac{457}{120}=3\frac{97}{120}\)
--Good luck--
\(2-\left(5\frac{3}{8}+x-7\frac{5}{24}\right)\)\(:16\frac{2}{3}=0\)
\(\Rightarrow\)\(2-\left(5\frac{3}{8}+x-7\frac{5}{24}\right)=0\)
\(\Rightarrow\)\(5\frac{3}{8}+x-7\frac{5}{24}=2\)
\(\Rightarrow5\frac{3}{8}+x=9\frac{5}{24}\)
\(\Rightarrow x=3\frac{5}{6}\)
( Cách làm thì đúng rồi nhưng đáp án tớ ko chắc chắn )
=10/17+-5/13+7/17+-8/13+-11/25
=1+-1+-11/25
=11/25
b ,
= 1+-2+3+-4+5+-6+......2011+-2012
=1+1+1+1+1.........+-2012
=1.2011+-2012
=2011+-2012
=-1
2.
2/3-x = 5/4
=>x=2/3-5/4
=>x=-7/12
b,
[124-(20-4x)]:30+7=11
=>124-(20-4x)] :30 =11-7
=>[124-(20-4x)]:30=4
=>124-(20-4x)=4x30
=>124-(20-4x)=120
=>20-4x=120-124
=>20-4x=4
=>4x=20-4
=>4x=16
=>x=16:4
=>x=4
bài 1
a, ghép cặp phân số 10/17 + 7/17 và 5/13 + -8/13
b, 1-2+3-4+5-6+.....+2011-2012
= ( 1-2) + ( 3-4) + ( 5-6) +....+(2011-2012)
= (-1) + (-1) + (-1) + ....+ (-1)
< từ 1 đến 2012 có 2012 số số hạng, suy ra có 1006 cặp mà mỗi cặp có giá trị = (-1) Suy ra tổng trên = (-1) * 1006=-1006
a) \(-\frac{3}{4}x+\frac{1}{6}x=1-2\frac{5}{9}\)
\(\left(-\frac{3}{4}+\frac{1}{6}\right).x=1-\frac{23}{9}\)
\(-\frac{7}{12}.x=-\frac{14}{9}\)
\(x=-\frac{14}{9}:\left(-\frac{7}{12}\right)\)
\(x=\frac{8}{3}\)
Vậy x = ...
b) \(\left|2x-\frac{3}{8}\right|+2\frac{3}{4}=3\frac{1}{16}\)
\(\left|2x-\frac{3}{8}\right|+\frac{11}{4}=\frac{49}{16}\)
\(\left|2x-\frac{3}{8}\right|=\frac{49}{16}-\frac{11}{4}\)
\(\left|2x-\frac{3}{8}\right|=\frac{5}{16}\)
\(\Rightarrow\left|2x-\frac{3}{8}\right|\in\text{{}\frac{5}{16};-\frac{5}{16}\)}
Nếu, \(2x-\frac{3}{8}=\frac{5}{16}\)
\(2x=\frac{11}{16}\)
\(x=\frac{11}{32}\)
Nếu, \(2x-\frac{3}{8}=-\frac{5}{16}\)
\(2x=\frac{1}{16}\)
\(x=\frac{1}{32}\)
Vậy \(x\in\text{{}\frac{1}{32};\frac{11}{32}\)}
\(\frac{7}{9}.\frac{3}{4}:\frac{5}{8}=\frac{7}{12}:\frac{5}{8}=\frac{7}{12}.\frac{8}{5}=\frac{14}{15}\)
\(\frac{8}{11}+\frac{8}{33}\times\frac{3}{4}\)
\(=\frac{8}{11}+\frac{2}{11}\)
\(=\frac{8+2}{11}\)
\(=\frac{10}{11}\)
\(\frac{8}{11}+\frac{8}{33}\cdot\frac{3}{4}=\frac{8}{11}+\frac{8\cdot3}{33\cdot4}=\frac{8}{11}+\frac{2}{11}=\frac{10}{11}\)