123 : x + 27 : x - 50 : x= 10. Hãy tìm x. Mọi người giúp mình với
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\(\frac{x+4}{2000}+\frac{x+3}{2001}=\frac{x+2}{2002}+\frac{x+1}{2003}\)
\(\Leftrightarrow\frac{x+2004}{2000}+\frac{x+2004}{2001}=\frac{x+2004}{2002}+\frac{x+2004}{2003}\)
\(\Leftrightarrow\left(x+2004\right)\left(\frac{1}{2000}+\frac{1}{2001}-\frac{1}{2002}-\frac{1}{2003}\right)\)
Dễ thấy: \(\left(\frac{1}{2000}+\frac{1}{2001}-\frac{1}{2002}-\frac{1}{2003}\right)\ne0\Rightarrow x+2004=0\Leftrightarrow x=-2014\)
a,x-235=445
x= 445 + 235
x = 680
vậy x= 680
b, 546 - (x - 123) = 239
x-123= 546 - 239
x-123 = 307
x=307+ 123
x= 430
vậy x= 430
c, 5. (x-17)+ 12= 122
5.(x-17)= 122 -12
5.(x-17) = 110
x-17= 110: 5
x-17= 22
x= 22+ 17
x= 39
Vậy x= 39
Bài 2.Tìm số tự nhiên x biết:
a,x-235=445
x=445+235
x=680
Vậy x=680
b,546-(x-123)=239
x-123=546-239
x-123=307
x=307+123
x=430
c,5.(x-17)+12=122
5(x-17)=122-12
5(x-17)=110
x-17=110:5
x-17=22
x=22+17
x=39
a) Ta có: \(\left|-5\right|+\left|x-1\right|=\left|7\right|\)
\(\Leftrightarrow\left|x-1\right|+5=7\)
\(\Leftrightarrow\left|x-1\right|=2\)
\(\Leftrightarrow\left[{}\begin{matrix}x-1=2\\x-1=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)
Vậy: \(x\in\left\{3;-1\right\}\)
b) Ta có: \(2\cdot\left|2x-4\right|-\left|-4\right|=\left|-50\right|\)
\(\Leftrightarrow4\cdot\left|x-2\right|-4=50\)
\(\Leftrightarrow4\cdot\left|x-2\right|=54\)
\(\Leftrightarrow\left|x-2\right|=\dfrac{27}{2}\)
\(\Leftrightarrow\left[{}\begin{matrix}x-2=\dfrac{27}{2}\\x-2=-\dfrac{27}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{31}{2}\left(loại\right)\\x=-\dfrac{23}{2}\left(loại\right)\end{matrix}\right.\)
Vậy: \(x\in\varnothing\)
a, | -5 | + | x-1 | = | 7 |
5 + | x - 1 | = 7
| x - 1 | = 2
TH1 x -1 = 2
x = 3
TH2 x -1 = -2
x= -1
b1 A=10000 B=23386
b2 a,x=5
b,x=4 x=2
có lẽ bn nên tự lm thì hơn
a: \(x^2-10x=-25\)
\(\Leftrightarrow x-5=0\)
hay x=5
b: \(x^2-6x+8=0\)
\(\Leftrightarrow\left(x-2\right)\left(x-4\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=4\end{matrix}\right.\)
a) \(1045:\left[215-\left(3x-24\right)\right]=5\)
\(\Rightarrow215-\left(3x-24\right)=1045:5\)
\(\Rightarrow215-\left(3x-24\right)=209\)
\(\Rightarrow3x-24=215-209\)
\(\Rightarrow3x-24=6\)
\(\Rightarrow3x=6+24\)
\(\Rightarrow3x=30\)
\(\Rightarrow x=30:3\)
\(\Rightarrow x=10\)
Vậy x = 10
b) \(\left[195-\left(15x+27\right)\right]\times39=4212\)
\(\Rightarrow195-\left(15x+27\right)=4212:39\)
\(\Rightarrow195-\left(15x+27\right)=108\)
\(\Rightarrow15x+27=195-108\)
\(\Rightarrow15x+27=87\)
\(\Rightarrow15x=87-27\)
\(\Rightarrow15x=60\)
\(\Rightarrow x=60:15\)
\(\Rightarrow x=4\)
Vậy x = 4
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