thực hiện phép tính
F=5^2.3^2+25.91
M=17.25+77.17-34
H=2665:[213-(21-19)^3]
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a) 2345 − 1000 : [19-2(21-18) 2 ]=2345-1000:1=1345
b) 205 − [ 1200 − ( 4 2 − 2.3 ) 3 ]=205-( 1200 − 1000 ) = 5
1) \(100-\left(3.5^2-2.3^2\right)\)
\(=100-\left(3.25-2.9\right)\)
\(=100-\left(75-18\right)\)
\(=100-57\)
\(=43\)
2) \(2665:\left[213-\left(17-3^2\right)\right]+347.5^2\)
\(=2665:\left[213-\left(17-9\right)\right]+347.25\)
\(=2665:\left[213-8\right]+8675\)
\(=2665:205+8675\)
\(=13+8675\)
\(=8688\)
a, 100 - ( 3. 52 - 2 . 32 )
= 100 - 3.( 52 - 6 )
= 100 - 3 .19
= 100 - 57
=43
b, 2665: [ 213 - ( 17 - 32 ) ] + 347 . 52
= 2665 : [213 - 8 ] + 8675
= 13 + 8675
=8688
1,100-(3.5\(^2\)-2.3\(^2\))
=100-(3.25-2.9)
=100-(75-18)
=100-57
=43
2,2665:\([\)213-(17-3\(^2\))\(]\)+347.5\(^2\)
=2665:\([\)213-8\(]\)+8675
=2665:205+8675
=13+8675
=8688
\(75.17-17.25+5^2\)
\(=75.17-17.25+25\)
\(=17.\left(75-25+25\right)\)
\(=17.\left(50+25\right)\)
\(=17.75\)
\(=1275\)
a) 81^11.3^17/27^10.9^15
=(9^2)^11.3^17/(3^3)^10.9^15
=3^44.3^17/3^30.3^30
=3^61/3^60
=3
b) A =( (2^12.3^5 - 2^12.3^4)/ (2^12.3^6 + 2^12.3^5) ) - ((5^10.7^3 - 5^10.7^4)/(5^9.7^3 + 5^9.2^3.7^3))
=(2^12.3^4(3-1))/2^12.3^5(3+1) - 5^10.7^3(1-7)/5^9.7^3(1+8)
=2/12- (-30/9)=1/6 + 10/3 = 7/2
a) 1-3+5-7+9-12+15-18
= (1+ 9) - (3+7) + (5+15) - (12+18)
= 10 - 10 + 20 - 30 = -10.
b) (-2)+5-7+9-11+13-15+19-21
= 5 - 11 - 2 -2 = 5 - (11+2+2)
= 5 - 15 = -10
Bài 1:
a) Ta có: 1-3+5-7+9-12+15-18
=(1+9)-(3+7)+(5+15)-(12+18)
=10-10+20-30
=-10
b) Ta có: \(\left(-2\right)+5-7+9-11+13-15+19-21\)
\(=3+2+2+4-21\)
\(=5+6-21\)
=11-21=-10
a: \(F=91\cdot100=9100\)