c) 23.15 – [ 115 + ( 12 - 25)]
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a) = 8 . 15 - [115- 72 ]
= 8 . 15 - [115- 49 ]
= 120 - 56
= 64
b) = 100 : {250 : [450 - (2.125 - 8.25)]}
= 100 : {250 : [450 - (250 - 200 )]}
= 100 : {250 : [450 - 50]}
= 100 : {250 :400}
= 100 : 0,265
= 0,00265
=
\(a,2^3.15-\left[115-\left(12-5\right)^2\right]\)
\(=8.15-\left[115-\left(12-5\right)^2\right]\)
\(=120-\left[115-7^2\right]\)
\(=120-\left[115-49\right]\)
\(=120-66\)
\(=54\)
\(b,100:\left\{250:\left[450-\left(2.5^3-2^3.25\right)\right]\right\}\)
\(=100:\left\{250:\left[450-\left(2.125-8.25\right)\right]\right\}\)
\(=100:\left\{250:\left[450-\left(250-200\right)\right]\right\}\)
\(=100:\left\{250:\left[450-50\right]\right\}\)
\(=100:\left\{250:400\right\}\)
\(=100:0,625\)
\(=160\)
\(2^3.15-\left[115-\left(12-5\right)^2\right]=8.15-\left[115-7^2\right]=120-\left[115-49\right]=120-66=54\)
\(100:\left\{250:\left[450-\left(4.5^3-2^2.25\right)\right]\right\}=100:\left\{250:\left[450-\left(4.125-4.25\right)\right]\right\}=100:\left\{250:\left[450-\left(500-100\right)\right]\right\}\)
\(=100:\left[250:\left(450-400\right)\right]=100:\left(250:50\right)=100:5=20\)
a) 1 5 + 2 5 = 1 + 2 5 = 3 5
b) 3 × 1 2 = 3 × 1 2 = 3 2
c) 1 - 2 3 + 1 6 = 1 - 12 18 + 3 18 = 1 - 15 18 = 3 18 = 1 6
d) 1 1 5 ÷ 1 1 2 = 6 5 ÷ 3 2 = 12 15 = 4 5
e) 3 5 + 2 5 × 1 6 = 3 5 + 2 30 = 20 30 = 2 3
a) 1 5 + 2 5 = 1 + 2 5 = 3 5
b) 3 × 1 2 = 3 × 1 2 = 3 2
c) 1 - 2 3 + 1 6 = 1 - 12 18 + 3 18 = 1 - 15 18 = 3 18 = 1 6
d) 1 1 5 ÷ 1 1 2 = 6 5 ÷ 3 2 = 12 15
e) 3 5 + 2 5 × 1 6 = 3 5 + 2 30 = 20 30 = 2 3
\(=23\cdot15-115+13=243\)
= 23 . 15 - ( 115 - 13 )
= 345 - 102 = 243