(x+2)+(x+4)+...+(x+98)+(x+100)=2700
x=?
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Tính tổng : 1 x 2 + 2 x 4 + 4 x 6 + .........+ 98 x 100
Gọi biểu thức trên là A, ta có :
A = 1x2 + 2x3 + 3x4 + 4x5 + ...+ 99x100
A x 3 = 1x2x3 + 2x3x3 + 3x4x3 + 4x5x3 + ... + 99x100x3
A x 3 = 1x2x3 + 2x3x(4-1) + 3x4x(5-2) + 4x5x(6-3) + ... + 99x100x(101-98)
A x 3 = 1x2x3 + 2x3x4 - 1x2x3 + 3x4x5 - 2x3x4 + 4x5x6 - 3x4x5 + ... + 99x100x101 - 98x99x100.
A x 3 = 99x100x101
A = 99x100x101 : 3
A = 333300
Đặt A = 1 . 2 . 3 + 2 . 3 . 4 + ... + 98 . 99 . 100
\(\Rightarrow\) 4A = 1 . 2 . 3 . 4 + 2 . 3 . 4 . (5 - 1) +...+ 98 . 99 . 100 . (101 - 97)
\(\Rightarrow\) 4A = 1 . 2 . 3 . 4 + 2 . 3 . 4 . 5 - 2 . 3 . 4 . 1 + ... + 98 . 99 . 100 . 101 - 98 . 99 . 100 . 97
\(\Rightarrow\) 4A = 98 . 99 . 100 . 101
\(\Rightarrow\) 4A = 97990200
\(\Rightarrow\) A = 24497550
Đặt A = 1 . 2 . 3 + 2 . 3 . 4 + ... + 98 . 99 . 100
=>4A = 1 . 2 . 3 . 4 + 2 . 3 . 4 . (5 - 1) +...+ 98 . 99 . 100 . (101 - 97)
=>4A = 1 . 2 . 3 . 4 + 2 . 3 . 4 . 5 - 2 . 3 . 4 . 1 + ... + 98 . 99 . 100 . 101 - 98 . 99 . 100 . 97
=>4A = 98 . 99 . 100 . 101 4A = 97990200
=>A = 24497550
Vậy A= 24497550
x + ( x + 2 ) + ( x + 4 ) + ( x + 6 ) + ( x + 8 ) +...........+ ( x + 98 ) + ( x + 100 ) = 2601
= (51x)[\(\left(100+2\right)x\left(\frac{100-2}{2}+1\right):2\)] =2601
đến đây e tự giải nốt nhé!
\(S=1\cdot2+2\cdot3+3\cdot4+...+99\cdot100\\ 3S=1\cdot2\cdot3+2\cdot3\cdot3+3\cdot3\cdot4+...+3\cdot99\cdot100\\ 3S=1\cdot2\cdot3+2\cdot3\cdot\left(4-1\right)+3\cdot4\cdot\left(5-2\right)+...+99\cdot100\cdot\left(101-98\right)\\ 3S=1\cdot2\cdot3+2\cdot3\cdot4-1\cdot2\cdot3+....+99\cdot100\cdot101-98\cdot99\cdot100\\ 3S=99\cdot100\cdot101\\ S=\dfrac{99\cdot100\cdot101}{3}=33\cdot100\cdot101=3300\cdot101=333300\)
x+ ( x+2) + (x+4) + ( x+6) +....... + (x+98)+ (x+100) =2601
x + x + 2 + x + 4 + x + 6 + ... + x + 98 + x + 100 = 2601
x + x + x + .... + x ( 51 chữ x ) + ( 2 + 4 + 6 + ... + 98 + 100 ) = 2601
51x + 2550 = 2601
51x = 51
x = 1
Ta có :
\(\frac{x+1}{100}+\frac{x+2}{99}=\frac{x+3}{98}+\frac{x+4}{97}\)
\(\Leftrightarrow\)\(\left(\frac{x+1}{100}+1\right)+\left(\frac{x+2}{99}+1\right)=\left(\frac{x+3}{98}+1\right)+\left(\frac{x+4}{97}+1\right)\)
\(\Leftrightarrow\)\(\frac{x+101}{100}+\frac{x+101}{99}=\frac{x+101}{98}+\frac{x+101}{97}\)
\(\Leftrightarrow\)\(\frac{x+101}{100}+\frac{x+101}{99}-\frac{x+101}{98}-\frac{x+101}{97}=0\)
\(\Leftrightarrow\)\(\left(x+101\right)\left(\frac{1}{100}+\frac{1}{99}-\frac{1}{98}-\frac{1}{97}\right)=0\)
Vì \(\frac{1}{100}+\frac{1}{99}-\frac{1}{98}-\frac{1}{97}\ne0\)
Nên \(x+101=0\)
\(\Rightarrow\)\(x=-101\)
Vậy \(x=-101\)
Chúc bạn học tốt ~
(x+2)+(x+4)+.......+(x+100)=2700
=.(x+x+...+x+x)+(2+4+...+98+100)=2700
=>(x . 50) + ((100+2)x50 : 2) = 2700
=> x . 50 + 2550 = 2700
=> x . 5 =2700-2550
=> x = 150:50
x= 3
ủng hộ nhé
<=>(x+x+x+...x)+(2+4+...+100)=2700
=>x*50+2550=2700
=>x*50=2700-2550
=>x*50=150
=>x=150:50
=>x=3