a) 16 - x = 21 - (-8) b) x - 32 = (-5) - 17
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a) x – 32 = − 5 − 17 ⇔ x – 32 = − 32 ⇔ x = − 32 + 32 ⇔ x = 0.
b) 16 – x = 21 – − 8 ⇔ 16 – x = 21 + 8 ⇔ 16 − x = 30 ⇔ − x = 30 − 16 ⇔ − x = 14 ⇔ x = − 14.
c) 106 − x = − 58 – 8 ⇔ 106 − x = − 66 ⇔ − x = − 66 − 106 ⇔ − x = − 172 ⇔ x = 172.
c) \(47-\left(x-15\right)=21\)
\(\Leftrightarrow x-15=47-21\)
\(\Leftrightarrow x-15=26\)
\(\Leftrightarrow x=26+15=41\)
d) \(-5-\left(24-x\right)=-11\)
\(\Leftrightarrow24-x=-5+11\)
\(\Leftrightarrow24-x=6\)
\(\Leftrightarrow x=24-6=18\)
a, x-32=(-5)-17
=>x-32=-22
=>x=(-22)+32
=>x=10
b,16-x=21-(-8)
=>16-x=29
=>x=16-29
=>x=-13
a) (2x-32):16=3
2x-32=3.16
2x-32=48
2x=48+32
2x=80
x=80:2
x=40
b) (7x -8:2):5=8
(7x-4):5=8
7x-4=8.5
7x-4=40
7x=40+4
a) (2x - 32) : 16 = 3 \(=\left(2x-32\right)=3.16=48\)
= \(\left(2x-32\right)=48\)
= \(2x=48+32=80\)
= \(2x=80\Rightarrow x=80:2=40\)
b) ( 7x - 8 :2) : 5 = 8
= \(\left(7x-8:2\right)=8.5=40\)
= \(\left(7x-8:2\right)=40\)
= \(\left(7x-8\right)=40.2=80\)
= \(\left(7x-8\right)=80\)
= \(7x=80+8=88\)
=>x = 88 : 7 = ......
c) 215 + ( x - 21) : 2 = 235
\(=\left(x-21\right):2=235-215=20\)
= \(\left(x-21\right):2=20\)
= \(\left(x-21\right)=20.2=40\)
= \(\left(x-21\right)=40\)
= \(\Rightarrow x=40+21=61\)
a) \(\frac{3}{16}+\frac{4}{15}+\frac{5}{16}+\frac{1}{15}\)
\(=\left(\frac{3}{16}+\frac{5}{16}\right)+\left(\frac{4}{15}+\frac{1}{15}\right)\)
\(=\frac{1}{2}+\frac{1}{3}\)
\(=\frac{5}{6}\)
b) \(\frac{6}{7}\times\frac{8}{15}\times\frac{7}{6}\times\frac{15}{16}\)
\(=\left(\frac{6}{7}\times\frac{7}{6}\right)\times\left(\frac{8}{15}\times\frac{15}{16}\right)\)
\(=1\times\frac{1}{2}=\frac{1}{2}\)
c) \(\frac{19}{20}\times\frac{13}{21}+\frac{9}{20}\times\frac{8}{21}\)
\(=\frac{19\times13}{20\times21}+\frac{9\times8}{20\times21}\)
\(=\frac{247}{420}+\frac{72}{420}\)
\(=\frac{319}{420}\)
a) 16-x=21+8
16-x=29
x=16-29
x=-13
b)x - 32= - 22
x = - 22 +32
x = 10
a) \(\text{16 - x = 21 - (-8).}\)
<=> \(\text{16 - x = 29.}\)
<=> \(x=-13.\)
Vậy \(x=-13.\)
b) \(\text{x - 32 = (-5) - 17}.\)
<=> \(\text{x - 32 = -22}.\)
<=> \(x=10.\)
Vậy \(x=10.\)