- 1)chứng tỏ rằng b=5+5^2+5^3+…5^29+5^30 chia hết cho 6
2)tìm x,y thuộc N biết 2^x+624=5^y
3)làm có lời giải giùm với
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2) bn tham khảo https://olm.vn/hoi-dap/detail/7423239791.html
1)
Có 6 chia hết cho 2x+1
=> 2x+1=Ư(6)={-6;-3;-2;-1;1;2;3;6}
Ta có bảng:
2x+1 | -6 | -3 | -2 | -1 | 1 | 2 | 3 | 6 |
2x | -7 | -4 | -3 | -2 | 0 | 1 | 2 | 5 |
x | \(\frac{-7}{2}\)(loại) | -2 (loại) | \(\frac{-3}{2}\)(loại) | -1 (loại) | 0 | \(\frac{1}{2}\)(loại) | 1 | \(\frac{5}{2}\)(loại) |
Vậy x=0 hoặc x=1
2)
A=5+52+53+...+520
=(5+52)+(53+54)+...+(519+520)
=(5+52)+52(5+52)+...518(5+52)
=30+52.30+54.30+56.30+..+518.30
=30(1+52+54+56+..+518) chia hết cho 30
<=> A là bội của 30 (đpcm)