29-3x5+45=.......
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\(\dfrac{45}{39}\) + \(\dfrac{53}{29}\) + \(\dfrac{5}{29}\) + \(\dfrac{33}{39}\)
= ( \(\dfrac{45}{39}\) + \(\dfrac{33}{39}\)) + ( \(\dfrac{53}{29}\) + \(\dfrac{5}{29}\))
= \(\dfrac{78}{39}\) + \(\dfrac{58}{29}\)
= 2 + 2
= 4
\(F=\sqrt[3]{27-27\sqrt{2}+18-2\sqrt{2}}\)\(+\sqrt[3]{27+27\sqrt{2}+18+2\sqrt{2}}\)
\(F=\sqrt[3]{\left(3-\sqrt{2}\right)^3}+\sqrt[3]{\left(3+\sqrt{2}\right)^3}\)
\(F=3+\sqrt{2}+3-\sqrt{2}=6\)
\(\sqrt[3]{45+29\sqrt{2}}+\sqrt[3]{45-29\sqrt{2}}\)
\(=\sqrt[3]{27+27\sqrt{2}+18+2\sqrt{2}}+\sqrt[3]{27-27\sqrt{2}+18-2\sqrt{2}}\)
\(=\sqrt[3]{\left(3+\sqrt{2}\right)^3}+\sqrt[3]{\left(3-\sqrt{2}\right)^3}\)
\(=3+\sqrt{2}+3-\sqrt{2}=6\)
29 + 34 + 29 +66 + 71 + 45 + 56 + 11 = 741
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29 + 34 + 29 +66 + 71 + 45 + 56 + 11
= ( 29 + 11 ) + ( 34 + 66 ) + ( 29 + 71 ) + 56 + 45
= 40 + 100 + 100 +56 + 45
= 341
C= 3√45+29√2+3√45−29√2
⇔\(C^3=45+29\sqrt{2}+45-29\sqrt{2}+3\sqrt[3]{45+29\sqrt{2}}.\sqrt[3]{45-29\sqrt{2}}\left(\sqrt[3]{45+29\sqrt{2}}+\sqrt[3]{45-29\sqrt{2}}\right)\\ C^3=90+3\sqrt[3]{343}.C\\ C^3=90+21C\\ C^3-21C-90=0\\ C^3-36C+15C-90\\ C\left(C-6\right)\left(C+6\right)+15\left(C-6\right)=0\\ \left(C-6\right)\left[C\left(C+6\right)+15\right]=0\\ \left(C-6\right)\left(C^2+6C+15\right)=0\\ \)
Mà C2+6C+15=(C+3)2+6 > 0
Nên C-6=0
⇒C=6
a) -79.|-45| - 21.|+45|
= -79.45 - 21.45
= 45. (-79-21)
= 45. (-100)
= -4500
b) 29.(23+15) - 23.(29+15)
= 29.23 + 29.15 - 23.29 - 23.15
= (29.23 - 23.29) + (29.15 - 23.15)
= 0 + 15.(29-23)
= 15.6
= 90
= 29-15+45
=14+45
=59
29-3x5+45 =59