\(C=\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\) tính giá trị của biểu thức
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\(\frac{5\times4^{15}\times9^9-4\times3^{20}\times8^9}{5\times2^9\times6^{19}-7\times2^{29}\times27^6}\)
\(=\frac{5\times\left(2^2\right)^{15}\times\left(3^2\right)^9-2^2\times3^{20}\times\left(2^3\right)^9}{5\times2^9\times\left(2\times3\right)^{19}-7\times2^{29}\times\left(3^3\right)^6}\)
\(=\frac{5\times2^{30}\times3^{18}-2^2\times3^{20}\times3^{27}}{5\times2^9\times2^{19}\times3^{19}-7\times2^{29}\times3^{18}}\)
\(=\frac{2^{29}\times3^{18}\times\left(5\times2-3^2\right)}{2^{28}\times3^{18}\times\left(5\times3-7\times2\right)}\)
\(=2\)
Chúc bạn học tốt ^^
\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}=\frac{5.\left(2^2\right)^{15}.\left(3^2\right)^9-2^2.3^{20}.\left(2^3\right)^9}{5.2^9.3^{19}.2^{19}-7.2^{29}.\left(3^3\right)^6}=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}=\frac{3^{18}.\left(5.2^{30}-2^{29}.3^2\right)}{3^{18}.\left(5.2^{28}.3-7.2^{29}\right)}=\frac{2^{28}.\left(5.2\right)}{2^{28}\left(5.3-7.2\right)}=\frac{10}{15-14}=\frac{10}{1}=10\)
Có j sai mong bỏ qua
Học tốt
Xét tử :
5.415.99 - 4.320.89
= 5.230.318 - 22 . 320 . 227
= 5 . 230 . 318 - 229 . 320
= 318 . 220 . ( 5 . 210 - 29 . 32 )
= 318 . 220 . [ 29 . ( 5 . 2 - 32 ) ]
= 318 . 220 . 29
= 318 . 229
Xét mẫu :
5.29.619 - 7.229.276
= 5 . 29 . 219 . 319 - 7 . 229 . 318
= 5 . 228 . 319 - 7 . 229 . 318
= 318 . 228 . ( 5 . 3 - 7 . 2 )
= 318 . 228
B = \(\frac{3^{18}.2^{29}}{3^{18}.2^{28}}=2\)
\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)\(=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)\(=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)\(=\frac{2^{29}.3^{18}\left(5.2-3^2\right)}{2^{28}.3^{18}\left(5.3-7.2\right)}=\frac{2.1}{1}=2\)
học tốt ~~~
\(\frac{5\cdot4^{15}\cdot9^9-4\cdot3^{20}\cdot8^9}{5\cdot2^9\cdot6^{19}-7\cdot2^{29}\cdot27^6}\\ =2\)
B= {[ 5 * (2^2)^15 * (3^2)^9 ] - [ (2^2) * 3^20 * (2^3)^9 ]} / {[ 5 * (2^9) * (2^19)*(3^19) ] - [ 7 * (2^29) * (3^3)^6 ]}
B= {[ 5 * (2^30) * (3^18) ] - [ (3^20) * (2^29) ]} / {[ 5 * (2^28) * (3^19) ] - [ 7 * (2^29) * (3^18) ]}
B= {[ (2^29) * (3^18) ] * [(5 * 2) - 3^2 ]} / {[ (2^28) * (3^18) ] - [(5 * 3) - (7 * 2)] }
B= [ (2^29) * (3^18) ] / [ (2^28) * (3^18) ]
B= [ (2^1) * (2^28) * (3^18) ] / [ (2^28) * (3^18) ]
B = 2
ta có \(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)=\(\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)=\(\frac{2^{29}.3^{18}\left(2.5-3^2\right)}{2^{28}.3^{18}\left(5.3-7.2\right)}\)=2
Đặt \(A=\frac{5.4^{15}.9^9+4.3^{20}.8^9}{5.2^9.6^{19}+7.2^{29}.27^6}\)
\(A=\frac{5.2^{30}.3^{18}+2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}+7.2^{29}.3^{18}}\)\(A=\frac{2^{28}\left(5.2^2.3^{18}+2.3^{20}\right)}{2^{28}\left(5.3^{19}+7.2.3^{18}\right)}\)
\(A=\frac{5.2^2.3^{18}+2.3^{20}}{5.3^{19}+7.2.3^{18}}\)\(A=\frac{3^{18}\left(5.2^2+2.3^2\right)}{3^{18}\left(5.3+7.2\right)}\)\(=\frac{5.2^2+2.3^2}{5.3+7.2}\)
\(=\frac{38}{29}=1\frac{9}{29}\)
\(C=\frac{5\cdot4^{15}\cdot9^9-4\cdot3^{20}\cdot8^9}{5\cdot2^9\cdot6^{19}-7\cdot2^{29}\cdot27^6}=\frac{5.2^{30}\cdot3^{27}-2^{29}\cdot3^{20}}{5\cdot2^{38}\cdot3^{19}-7\cdot2^{29}\cdot3^{18}}=\frac{\left(5\cdot2\cdot3^7-1\right)\left(2^{29}\cdot3^{20}\right)}{\left(5\cdot2^9\cdot3-7\right)\left(2^{29}\cdot3^{18}\right)}\)
Ra kết quả hơi to nên không tính. Bạn tính hộ mình nhé OK!!!