Tìm x
a) 4, 5 x x = 11, 06 + 2,44
b) 9,9 : x = 6,4 – 5,08
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a) \(\dfrac{4}{7}\times x=\dfrac{5}{9}+\dfrac{1}{5}=\dfrac{34}{45}\)
\(x=\dfrac{34}{45}:\dfrac{4}{7}=\dfrac{119}{90}\)
b) \(\dfrac{11}{15}:x=\dfrac{2}{3}-\dfrac{9}{15}=\dfrac{1}{15}\)
\(x=\dfrac{11}{15}:\dfrac{1}{15}=11\)
a) 4/7 x X - 1/5 = 5/9
4/7 x X = 5/9 + 1/5
4/7 x X = 34/45
X = 34/45 : 4/7
X = 119/90
b)9/15 + 11/15 : X = 2/3
11/15 : X = 2/3 - 9/15
11/15 : X = 1/15
X = 11/15 : 1/5
X = 11
a: \(\Leftrightarrow x=\dfrac{33}{20}:\dfrac{11}{8}=\dfrac{33}{20}\cdot\dfrac{8}{11}=3\cdot\dfrac{2}{5}=\dfrac{6}{5}\)
b: \(\Leftrightarrow x=5:\dfrac{4}{7}=\dfrac{35}{4}\)
a: x=-5/11+2/11=-3/11
b: =>x=-3/24+20/24+1/24=18/24=3/4
c: =>5/8-x=1/9+5/4=4/36+45/36=49/36
=>x=5/8-49/36=-53/72
d: =>2/3-x=1/3
=>x=1/3
e: =>1/5:x=12/35
=>x=7/12
\(a,\frac{1}{3}+\frac{6}{11}.\frac{22}{5}-\frac{3}{4}:1,5=\frac{1}{3}+\frac{6.2}{5}-\frac{3}{4}:\frac{3}{2}=\frac{1}{3}+\frac{12}{5}-\frac{1}{2}=\frac{10}{30}+\frac{72}{5}-\frac{15}{30}=\frac{67}{30}\)
\(b, 3.3,5.6+2.6,4.9+1,8=18.3,5+18.6,4+1,8=18\left(3,5+6,4\right)+1,8=18.9,9+1,8=1,8.99+1,8=1,8\left(1+99\right)=1,8.100=180\)
b ) 3 x 3,5 x 6 + 2 x 6,4 x 9 + 1,8
= 18 x 3,5 + 18x 6,4 + 18 x 0,1
= 18 ( 3,5 + 6,4 + 0,1)
= 18 x 10
= 180
a) \(3\times x\times5=3,45\)
\(\Rightarrow\left(3\times5\right)\times x=3,45\)
\(\Rightarrow15\times x=3,45\)
\(\Rightarrow x=3,45:15\)
\(\Rightarrow x=0,23\)
\(a,3\times x\times5=3,45\\ 15\times x=3,45\\ x=0,23\)
Lời giải:
a.
$\frac{2}{3}+\frac{1}{3}:3\times x=20\text{%}$
$\frac{2}{3}+\frac{1}{9}\times x=\frac{1}{5}$
$\frac{1}{9}\times x=\frac{1}{5}-\frac{2}{3}=\frac{-7}{15}$
$x=\frac{-7}{15}: \frac{1}{9}=\frac{-21}{5}$
b.
$\frac{3-x}{5-x}=\frac{6}{11}$
$\Rightarrow 6(5-x)=11(3-x)$
$\Rightarrow 30-6x=33-11x$
$\Rightarrow 5x=3$
$\Rightarrow x=\frac{3}{5}$
a: x=9/2-3/7=57/14
b: =>x=7/5x5/7=1
c: =>x=11/3:3/8=11/3x8/3=88/9
a : x = \(\dfrac{9}{2}\) - \(\dfrac{3}{7}\) = \(\dfrac{57}{14}\)
b : = > x = \(\dfrac{7}{5}\) x\(\dfrac{5}{7}\) = 1
c : = > \(\dfrac{11}{3}\) : \(\dfrac{3}{8}\) = \(\dfrac{11}{3}\) x \(\dfrac{8}{3}\) = \(\dfrac{88}{9}\)
a)
4 , 5 × x = 11 , 06 + 2 , 44 4 , 5 × x = 13 , 5 x = 13 , 5 : 4 , 5 x = 3
b)
9 , 9 : x = 6 , 4 − 5 , 08 9 , 9 : x = 1 , 32 x = 9 , 9 : 1 , 32 x = 7 , 5