Tìm xx biết:
xx : 5 = 83
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\(\dfrac{-12}{25}.\left(\dfrac{3}{4}-x+\dfrac{6}{-11}-\dfrac{5}{6}\right)=0\)
\(\dfrac{3}{4}-x+\dfrac{-6}{11}-\dfrac{5}{6}=0\)
\(\dfrac{3}{4}-x+\dfrac{-91}{66}=0\)
\(\dfrac{3}{4}-x=0-\left(\dfrac{-91}{66}\right)\)
\(\dfrac{3}{4}-x=\dfrac{91}{66}\)
\(x=\dfrac{-83}{132}\)
- 25 - ( x + 5 ) = 415 + 5( x - 83 )
- 25 - x-5= 415+ 5x -415
- 30-x = 415 -415 +5x
-30-x = 5x
-30= x+ 5x
-30 = 6x
-30:6= x
-5 = x
Vậy...
-25 - ( x + 5 ) = 415 + 5( x - 83 )
-25 - x - 5 = 415 + 5x - 415
( -25 - 5 ) - x = ( 415 - 415 ) +5x
-30 - x = 5x
-30 = 5x + x
-30 = 6x
x = ( -30) :6
* = -5
\(x^2\left(x-5\right)+x-5=0\)
\(\Rightarrow x^2\left(x-5\right)+\left(x-5\right)=0\)
\(\Rightarrow\left(x-5\right)\left(x^2-1\right)=0\)
\(\Rightarrow\left(x-5\right)\left(x-1\right)\left(x+1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x-5=0\\x-1=0\\x+1=0\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=5\\x=1\\x=-1\end{matrix}\right.\)
\(x^2\left(x-5\right)+x-5=0\)
\(\Leftrightarrow x-5=0\)
hay x=5
\(x-\dfrac{3}{4}=2\)
\(x=2+\dfrac{3}{4}\)
\(x=\dfrac{11}{4}\)
xx : 5 = 83
xx = 83 x 5 = 415
xx:5=83
xx = 83x5
xx = 415