Tính:
7 x 5 + 15
7 x 9 +17
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\(257-\left(3x+25\right)=157\)
\(3x+25=257-157\)
\(3x+25=100\)
\(3x=75\)
\(x=25\)
vay \(x=25\)
\(x-140:35=270\)
\(x-4=270\)
\(x=274\)
vay \(x=274\)
\(23-\left(x:13\right)=18\)
\(\frac{x}{13}=5\)
\(\frac{x}{13}=\frac{65}{13}\)
\(\Rightarrow x=65\)
vay \(x=65\)
\(9\left(x+5\right)-13=671\)
\(9x+45=684\)
\(9x=639\)
\(x=71\)
vay \(x=71\)
\(9\left(4x\right)-13=24\)
\(36x=37\)
\(x=\frac{37}{36}\)
vay \(x=\frac{37}{36}\)
\(\left(x-5\right)-34:17=1\)
\(\left(x-5\right)-2=1\)
\(x-5=3\)
\(x=8\)
vay \(x=8\)
\(\left(2x-7\right).3=3\)
\(2x-7=1\)
\(2x=8\)
\(x=4\)
vay \(x=4\)
\(\left(3x-5\right):2=4.5\)
\(\left(3x-5\right):2=20\)
\(3x-5=10\)
\(3x=15\)
\(x=5\)
vay \(x=5\)
con lai lam tuong tu
mk moi tay roi nen ban tu lam vay
\(a,157.17-157.7=157\left(17-7\right)=1570\)
\(b,5.\left(-3+2\right)-7.\left(5-4\right)=-5-7=-12\)
\(c,17.\left(-84\right)+17\left(-16\right)=17\left[\left(-84\right)+\left(-16\right)\right]=-1700\)
\(d,-145.\left(13-57\right)+57.\left(10-145\right)=6380-7695=-1315\)
\(e,199.\left(15-17\right)-199.\left(-17+5\right)=199.10=1990\)
1) Ta có: \(\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{7}{25}\cdot\dfrac{5}{7}\right)\)
\(=\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{1}{5}\right)\)
=0
2) Ta có: \(\dfrac{8}{17}\cdot\dfrac{4}{15}+\dfrac{8}{17}\cdot\dfrac{22}{15}-\dfrac{8}{15}\cdot\dfrac{9}{17}\)
\(=\dfrac{8}{17}\left(\dfrac{4}{15}+\dfrac{22}{15}-\dfrac{9}{15}\right)\)
\(=\dfrac{8}{17}\cdot\dfrac{15}{15}=\dfrac{8}{17}\)
3) Ta có: \(\dfrac{2021}{2}\cdot\dfrac{1}{3}+\dfrac{4042}{4}\cdot\dfrac{1}{5}+\dfrac{6063}{3}\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)+2021\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{8}{15}+\dfrac{2021}{2}\cdot\dfrac{44}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{52}{15}\)
\(=\dfrac{52546}{15}\)
4) Ta có: \(\dfrac{4}{7}\cdot\dfrac{2}{13}+\dfrac{8}{13}:\dfrac{7}{4}+\dfrac{4}{7}:\dfrac{13}{2}+\dfrac{4}{7}\cdot\dfrac{1}{13}\)
\(=\dfrac{4}{7}\left(\dfrac{2}{13}+\dfrac{8}{13}+\dfrac{2}{13}+\dfrac{1}{13}\right)\)
\(=\dfrac{4}{7}\)
Câu 1: Tìm x:
a) 2/5× x =(thiếu đề)
8/7: x =4/5
x=8/7:4/5
x=10/7
Câu 2: Tính bằng cách thuận tiện nhất
5/9× 8/17 + 4/9 × 8/17
=(5/9+4/9)x8/17
=1x8/17=8/17
= \(\frac{2}{9}\left(\frac{5}{17}+\frac{12}{17}\right)+\frac{7}{9}\)
= \(\frac{2}{9}\times1+\frac{7}{9}\)
= \(1\)
xin tiick
1: \(=75\left(27+25-2\right)=75\cdot50=3750\)
2: \(=15\left(23+37\right)+55=15\cdot60+55=955\)
3: \(=36\cdot14+36\cdot17+36\cdot69\)
\(=36\cdot100=3600\)
4: \(=200\cdot\left(32+68\right)=200\cdot100=20000\)
7 x 5 + 15 = 35 + 15 = 50
7 x 9 + 17 = 63 + 17 = 80