Question

[TOAN 2000]

Cho M=1+2^1+2^2+...+2^50 va N=2^51

So sanh M va N

Answer 1

[Minh Hiền]

\(M=1+2+2^2+...+2^{50}\)

\(\Rightarrow2M=2.\left(1+2+2^2+...+2^{50}\right)\)

\(2M=2+2^2+2^3+...+2^{51}\)

\(\Rightarrow2M-M=\left(2+2^2+2^3+...+2^{51}\right)-\left(1+2+2^2+...+2^{50}\right)\)

\(\Rightarrow M=2^{51}-1<2^{51}=N\)

Vậy M < N.