2/5+3/5.(3x-3,7)=-53/10
Giải hộ mik nha.Cảm ơn
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\(\frac{2}{5}+\frac{3}{5}\times\left(3x-3,7\right)=-\frac{53}{10}\)
\(\frac{3}{5}\times\left(3x-3,7\right)=-\frac{53}{10}-\frac{2}{5}\)
\(\frac{3}{5}\times\left(3x-3,7\right)=-\frac{57}{10}\)
\(\left(3x-3,7\right)=-\frac{57}{10}\div\frac{3}{5}\)
\(3x-3,7=-\frac{19}{2}\)
\(3x=-\frac{19}{2}+3,7\)
\(3x=-\frac{29}{5}\)
\(x=-\frac{29}{5}\div3\)
\(x=-\frac{29}{15}\)
Chúc bạn học tốt ^^
3/5.(3x-37/10)= -53/10-2/5
3/5.(3x-37/10)=-57/10
3x-37/10 =-57/10 : 3/5
3x-37/10=-19/2
3x =-19/2+37/10
3x =-29/15
x=-29/15 : 3
x=-29/15
x : 2/5 + 3/5 . (3x - 3,7) = -53/10
x. 2/5 + 3/5. 3x - 3/5. 37/10 = -53/10
x . 5/2 + 9/5.x - 111/50 = -53/10
x. ( 5/2 + 9/5) = -53/10 + 111/50
x . 43/10 = -73/25
x = -73/25 : 43/10
x = -146/215
\(\frac{2}{5}+\frac{3}{5}\times\left(3x-3,7\right)=-\frac{53}{10}\)
\(\frac{3}{5}\times\left(3x-3,7\right)=-\frac{53}{10}-\frac{2}{5}\)
\(\frac{3}{5}\times\left(3x-3,7\right)=\frac{-53-4}{10}\)
\(\frac{3}{5}\times\left(3x-3,7\right)=-\frac{57}{10}\)
\(3x-3,7=-\frac{57}{10}\div\frac{3}{5}\)
\(3x-3,7=-\frac{57}{10}\times\frac{5}{3}\)
\(3x-3,7=-\frac{19}{2}\)
\(3x=-\frac{19}{2}+\frac{37}{10}\)
\(3x=\frac{-95+37}{10}\)
\(3x=-\frac{58}{10}\)
\(x=-\frac{29}{5}\div3\)
\(x=-\frac{29}{5}\times\frac{1}{3}\)
\(x=-\frac{29}{15}\)
Chúc bạn học tốt
\(\frac{2}{5}+\frac{3}{5}.\left(3x-3,7\right)=\frac{-53}{10}\)
\(\frac{3}{5}.\left(3x-3,7\right)=\frac{-57}{10}\)
\(\left(3x-3,7\right)=\frac{-19}{2}\)
\(3x=-5,8\)
\(x=\frac{-29}{15}\)
Vậy \(x=\frac{-29}{15}\)
Dễ quá mà bn ko biết làm à
2/3x -3/2x=5/12
x(2/3-3/2)=5/12
x=5/12. (-5/6)
x=-25/72
a) \(x=-\frac{1}{2}\)
b) \(x=-\frac{29}{15}\)
c) \(x=\frac{5}{6}\)
**** cho mình nhé
a) \(\frac{2}{5}+\frac{3}{5}.\left(3x-3,7\right)=\frac{-53}{10}\)
=> \(\frac{3}{5}.\left(3x-3,7\right)=\frac{-53}{10}-\frac{2}{5}\)
=> \(\frac{3}{5}.\left(3x-3,7\right)=\frac{-57}{10}\)
=> \(\left(3x-3,7\right)=\frac{-19}{5}\)
=>\(3x=\frac{-19}{5}+\frac{37}{10}\)
=>\(3x=\frac{-1}{10}\)
=>\(x=\frac{-1}{30}\)
Ko biết đúng hay sai!!?
a) \(\left(\dfrac{3}{5}+0,415-\dfrac{3}{200}\right).2\dfrac{2}{3}.0,25\)
\(=\left(\dfrac{3}{5}+\dfrac{83}{200}-\dfrac{3}{200}\right).\dfrac{8}{3}.\dfrac{1}{4}\)
\(=\left(\dfrac{3}{5}+\dfrac{2}{5}\right).\dfrac{2}{3}\)
\(=1.\dfrac{2}{3}=\dfrac{2}{3}\)
b) \(\dfrac{2}{5}+\dfrac{3}{5}.\left(3x-3,7\right)=\dfrac{-53}{10}\)
\(\dfrac{3}{5}.\left(3x-\dfrac{37}{10}\right)=\dfrac{-53}{10}-\dfrac{2}{5}=\dfrac{-57}{10}\)
\(3x-\dfrac{37}{10}=\dfrac{-57}{10}:\dfrac{3}{5}=\dfrac{-19}{2}\)
\(3x=\dfrac{-19}{2}+\dfrac{37}{10}=\dfrac{-29}{5}\)
\(x=\dfrac{-29}{5}:3=\dfrac{-29}{15}\)