Tính giá trị biểu thức A = 1.2.3 + 3.4.5 + 5.6.7 + … + 99.100.101.
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=> 4E = 1.2.3.4 + 2.3.4.4 + 3.4.5.4 + .... + 99.100.101.4
=> 4E = 1.2.3.( 4 - 0 ) + 2.3.4.( 5 - 1 ) + 3.4.5.( 6 - 2 ) + .... + 99.100.101.( 102 - 98 )
=> 4E = 1.2.3.4 - 0.1.2.3 + 2.3.4.5 - 1.2.3.4 + 3.4.5.6 - 2.3.4.5 + ... + 99.100.101.102 - 98.99.100.101
=> 4E = ( 1.2.3.4 - 1.2.3.4 ) + ( 2.3.4.5 - 2.3.4.5 ) + + ... + ( 98.99.100.101 - 98.99.100.101 ) + 99.100.101.102
=> 4E = 99.100.101.102
=> E = ( 99.100.101.102 ) : 4
Ta có: A = 1.2.3+3.4.5+5.6.7+...+99.100.101
A = 1.3 (5-3) + 3.5 (7-3) + 5.7 (9-3) + ............ + 99.101 (103 - 3)
A = (1.3.5 + 3.5.7 + 5.7.9 + .......... + 99.101.103) - (1.3.3 + 3.5.3 + ....... + 99.101.3)
A = (15+99.101.103.105) : 8 - 3.(1.3 + 3.5 +5.7 + ...... + 99.101)
A = 13517400 - 3.171650
A = 13002450
1.2.3.4+2.3.4.5+3.4.5.6+...+97.98.99.100
4S=(1.2.3+2.3.4+3.4.5+4.5.6+...+98.99.100). 4
4S=1.2.3(4-0)+2.3.4(5-1)+3.4.5(6-2)+4.5.6(7-3)+...+98.99.100(101-97)
4S=1.2.3.4+2.3.4.5-1.2.3.4+3.4.5.6-2.3.4.5+4.5.6.7-3.4.5.6+...98.99.100.101-97.98.99.100
4S=1.2.3.4-1.2.3.4+2.3.4.5-2.3.4.5+3.4.5.6-3.4.5.6+...+97.98.99.100-97.98.99.100+98+99.100+101
4S=98.99.100.101
Vậy S = 98.99.100.101/4 = 24497550
\(A=1.2.3+3.4.5+5.6.7+...+99.100.+101\)
\(A=1.3\left(5-3\right)+3.5\left(7-3\right)+5.7\left(9-3\right)+...+99.100\left(103-3\right)\)
\(=\left(1.3.5+3.5.7+5.7.9+99.101.103\right)-\left(1.3.3+3.5.3+99.101.3\right)\)
\(=\left(15+99.101.103.105\right):8-3.\left(1.3+3.5+5.7+99.101\right)\)
\(=13517400-3.171650\)
\(=13002450\)
Rút gọn mỗi số hãng của số ta được :
\(C=\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{99.101}\)
\(=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{99}-\frac{1}{101}\)
\(=1-\frac{1}{101}=\frac{100}{101}\)
Vậy C = 100/101
\(C=\frac{4}{1.2.3}+\frac{8}{3.4.5}+\frac{12}{5.6.7}+...+\frac{200}{99.100.101}\)
\(=\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{99.101}\)
\(=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{99}-\frac{1}{101}\)
\(=1-\frac{1}{101}\)
\(=\frac{101}{101}-\frac{1}{101}\)
\(=\frac{100}{101}\)