2/8x11+2/11x14...+2/290x293=
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$\frac{2}{5\times 8}+\frac{2}{8\times 11}+\frac{2}{11\times 14}+...+\frac{2}{95\times 98}$
$=\left(\frac{3}{5\times 8}+\frac{3}{8\times 11}+\frac{3}{11\times 14}+...+\frac{3}{95\times 98}\right)\times \frac{2}{3}$
$=\left(\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{14}+...+\frac{1}{95}-\frac{1}{98}\right)\times \frac{2}{3}$
$=\left(\frac{1}{5}-\frac{1}{98}\right)\times \frac{2}{3}$
$=\frac{93}{490}\times \frac{2}{3}$
$=\frac{93\times 2}{490\times 3}$
$=\frac{31\times 1}{245\times 1}$
$=\frac{31}{245}$
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\(E=\frac{3^2}{8.11}+\frac{3^2}{11.14}+......+\frac{3^2}{197.200}\)
\(E=3.\left(\frac{3}{8.11}+\frac{3}{11.14}+......+\frac{3}{197.200}\right)\)
\(E=3.\left(\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+.....+\frac{1}{197}-\frac{1}{200}\right)\)
\(E=3.\left(\frac{1}{8}-\frac{1}{200}\right)\)
\(E=3.\frac{3}{25}\)
\(E=\frac{9}{25}\)
\(\frac{1}{3}E=\frac{3}{8x11}+\frac{3}{11x14}+..+\frac{3}{197x200}\)
\(\frac{1}{3}E=\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}+.+\frac{1}{197}-\frac{1}{200}\)
\(\frac{1}{3}E=\frac{1}{8}-\frac{1}{200}\)
\(\frac{1}{3}E=\frac{3}{25}\)
\(E=\frac{9}{25}\)
\(\frac{2}{5\times8}+\frac{2}{8\times11}+\frac{2}{11\times14}+...+\frac{2}{95\times98}\)
\(=\left(\frac{3}{5\times8}+\frac{3}{8\times11}+\frac{3}{11\times14}+...+\frac{3}{95\times98}\right)\times\frac{2}{3}\)
\(=\left(\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{14}+...+\frac{1}{95}-\frac{1}{98}\right)\times\frac{2}{3}\)
\(=\left(\frac{1}{5}-\frac{1}{98}\right)\times\frac{2}{3}\)
\(=\frac{93}{490}\times\frac{2}{3}\)
\(=\frac{93\times2}{490\times3}\)
\(=\frac{31\times1}{245\times1}\)
\(=\frac{31}{245}\)
2/5x8+2/8x11+2/11x14+...+2/95x98
=2(1/5x8+1/8x11+1/11x14+...+1/95x98) (khoang cach tu 5-8;8-11;11-14;...;95-98 la 3) suy ra =2/3(1/5-1/8+1/8-1/11+1/11-1/14+...+1/95-1/98)
=2/3(1/5-1/98)=2/3x93/5x98=31/245
a) \(\frac{3}{4\times9}+\frac{3}{9\times14}+...+\frac{3}{54\times59}+\frac{3}{59\times64}\)
\(=\frac{3}{5}\times\left(\frac{5}{4\times9}+\frac{5}{9\times14}+...+\frac{5}{59\times64}\right)\)
\(=\frac{3}{5}\times\left(\frac{9-4}{4\times9}+\frac{14-9}{9\times14}+...+\frac{64-59}{59\times64}\right)\)
\(=\frac{3}{5}\times\left(\frac{1}{4}-\frac{1}{9}+\frac{1}{9}-\frac{1}{14}+...+\frac{1}{59}-\frac{1}{64}\right)\)
\(=\frac{3}{5}\times\left(\frac{1}{4}-\frac{1}{64}\right)\)
\(=\frac{9}{64}\)
b) \(\frac{2}{8\times11}+\frac{2}{11\times14}+...+\frac{2}{23\times26}+\frac{2}{26\times29}\)
\(=\frac{2}{3}\times\left(\frac{3}{8\times11}+\frac{3}{11\times14}+...+\frac{3}{26\times29}\right)\)
\(=\frac{2}{3}\times\left(\frac{11-8}{8\times11}+\frac{14-11}{11\times14}+...+\frac{29-26}{26\times29}\right)\)
\(=\frac{2}{3}\times\left(\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+...+\frac{1}{26}-\frac{1}{29}\right)\)
\(=\frac{2}{3}\times\left(\frac{1}{8}-\frac{1}{29}\right)\)
\(=\frac{7}{116}\)
Đặt biểu thức cần tính là A
(3/2)xA=3/8x11+3/11x14+...+3/290x293
(3/2)xA=(11-8)/8x11+(14-11)/11x14+...+(293-290)/290x293
(3/2)xA=1/8-1/11+1/11-1/14+...+1/290-1/293=1/8-1/293
A=[(1/8-1/293)x2]:3