Tính nhanh : 1-2+3-4+....-98+99
Giúp vs ạ
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\(A=\dfrac{1}{3}+\dfrac{1}{6}+...+\dfrac{1}{4950}=\dfrac{2}{6}+\dfrac{2}{12}+...+\dfrac{2}{9900}=2.\left(\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{99.100}\right)=2.\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{99}-\dfrac{1}{100}\right)=2.\left(\dfrac{1}{2}-\dfrac{1}{100}\right)=2.\dfrac{49}{100}=\dfrac{49}{50}\)
<=> P = 2100 - ( 299 + 298 + ..... + 22 + 2 + 1 )
Đặt A = 1 + 2 + 22 + 23 + ...... + 298 + 299
<=> 2A = 2.( 1 + 2 + 22 + ..... + 298 + 299 )
<=> 2A = 2 + 22 + 23 + ...... + 299 + 2100
<=> 2A - A = ( 2 + 22 + 23 + ..... + 299 + 2100 ) - ( 1 + 2 + 22 + ..... + 298 + 299 )
<=> A = 2100 - 1
=> P = 2100 - ( 2100 - 1 )
=> P = - 1
Vậy P = - 1
\(A=\frac{\left[\left(25-1\right):1+1\right]\left(25+1\right)}{2}=325.\)
\(B=\frac{\left[\left(51-3\right):2+1\right]\left(51+3\right)}{2}=675\)
\(C=\frac{\left[\left(81-1\right):4+1\right]\left(81+1\right)}{2}=861\)
a, <=> (3+7+...+97) - (1+5+...+99)
\(=\left(\frac{97-3}{4}+1\right)\left(\frac{97+3}{2}\right)-\left(\frac{99-1}{4}+1\right)\left(\frac{99+1}{2}\right)\)
1225 - 1275 = -50
b, Tương tự
a) 67+135+33
= ( 67+33)+135
= 100 + 135
= 235
b) 146+121+54+379
= ( 146+54)+( 121+379)
= 200 + 500
= 700
c) 198+232-98-32
= ( 232-32)+(198-98)
= 200 + 100
= 300
d)1+2+3+4+.........+50
= ( 50+1) x 50:2 =1275
e)2+4+6+8+..........+100
= ( 100+2) x 50 : 2 =2550
f) 23 x 56 +56
= 1288 + 56
= 1344
g)32 x 19+32
= 608 + 32
= 640
\(a.67+135+33\)
\(=\left(67+33\right)+135\)
\(=100+135=235\)
\(b.141+121+54+379\)
\(=\left(146+54\right)+\left(121+379\right)\)
\(=200+500=700\)
\(c.198+232-98-32\)
\(=\left(232-32\right)+\left(198-98\right)\)
\(=200+100=300\)
\(f.23.56+56=1288+56=1344\)
\(g.32.19+32=608+32=640\)
tính nhanh (2/3+3/4+5/6+...+99/100).(1/2+2/3+3/4+...+98/99)-(1/2+1/3+...+99/100).(2/3+2/4+...+98/99)
1-2+3-4+....-98+99
= ( -1) + (-1)+....+(-1)
= -1.25
=- 25
Mk thấy chỗ phần cuối sai sai, sao lại là -98 +99 được phải là + 98-99
\(\text{1−2+3−4+5−6+7−8+......+97−98+99}\)
\(\text{=(1−2)+(3−4)+(5−6)+(7−8)+......+(97−98)+99}\)
\(\text{=(−1)+(−1)+(−1)+(−1)+......+(−1)+99( có 49 chữ số (−1)}\)
\(\text{=(−1).49+99}\)
\(\text{=(−1).49+99}\)
\(\text{=50}\)
học tốt!!