Tìm x bằng quy tắc chuyển vế :
a)-18-( x-6)=0
b)29-(10+29)= x-(27-9)
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1,7-(18+x)=-15
<=>18+x=7+15
<=>18+x=22
<=>x=4
2,(x-17)-(-3)=0
<=>x-17+3=0
<=>x-17=-3
,<=>x=14
<=>
1,
7 - ( 18 + x ) = - 15
18 + x = 7 + 15
18 + x = 22
x = 22 - 18
x = 4
2,
( x - 17 ) - ( - 3 ) = 0
( x - 17 ) + 3 = 0
x - 17 = - 3
x = -3 + 17
x = 14
3, -18 - ( x - 6 ) = 0
-18 = x- 6
x = - 18 + 6
x = - 12
4, 29 - ( 10 + 29 ) = x - ( 27 - 9 )
-10 = x - 18
x = - 10 + 18
x = 8
a) -84 - (-18 - 6) = x + (-20)
-84 + 18 + 6 = x - 20
-84 + 18 + 6 + 20 = x
=> x = -40
\(-84-\left(-18-6\right)=x+\left(-20\right)\)
\(\Leftrightarrow x=\left(-20\right)+84+\left(-18-6\right)\)
\(\Leftrightarrow x=40\)
P/s tham khảo nha
a,\(7-\left(18+x\right)=-15\)
\(18+x=7-\left(-15\right)\)
\(18+x=22\)
\(x=4\)
b,\(\left(x-17\right)-\left(-3\right)=0\)
\(x-17=-3\)
\(x=14\)
c,\(-18-\left(x-6\right)=0\)
\(x-6=-18\)
\(x=-12\)
d,\(29-\left(10+29\right)=x-\left(27-9\right)\)
\(x-18=-10\)
\(x=8\)
a) \(7-\left(18+x\right)=-15\)
\(\Leftrightarrow18+x=7+15\)
\(\Leftrightarrow18+x=22\)
\(\Leftrightarrow x=22-18\)
\(\Leftrightarrow x=4\)
b) \(\left(x-17\right)-\left(-3\right)=0\)
\(\Leftrightarrow\left(x-17\right)+3=0\)
\(\Leftrightarrow x-17=0-3\)
\(\Leftrightarrow x-17=-3\)
\(\Leftrightarrow x=-3+17\)
\(\Leftrightarrow x=14\)
c) \(-18-\left(x-6\right)=0\)
\(\Leftrightarrow x-6=0+\left(-18\right)\)
\(\Leftrightarrow x-6=-18\)
\(\Leftrightarrow x=-18+6\)
\(\Leftrightarrow x=-12\)
d) \(29-\left(10+29\right)=x-\left(27-9\right)\)
\(\Leftrightarrow29-10-29=x-27+9\)
\(\Leftrightarrow-10=x-27+9\)
\(\Leftrightarrow x-27=-10-9\)
\(\Leftrightarrow x-27=-19\)
\(\Leftrightarrow x=-19+27\)
\(\Leftrightarrow x=8\)
a,\(2x+12-18=x+4-18\)
\(\Rightarrow2x-x=4-1+18-12\)
\(\Rightarrow x=9\)
b,\(-5x+10-102=-6x-102\)
\(\Rightarrow-5x+6x=-102+102-10\)
\(\Rightarrow x=-10\)
a, 2x + 12 - 18 = x + 4 - 18
2x -x = 4 - 18 - 12 + 18
x = - 8
b, - 5x + 10 - 102 = - 6x - 102
- 5x + 6x = -102 - 10 + 102
x = - 10
VERY GOOD!!!
Ta có :
a. -23-x=15
→x=-23-15
→x=-38
b. -18-(x-25)=-5
→(x-25)=-18-(-5)
→x-25=-13
→x=-13+25
→x=12
mình làm hai câu một nhé
a)(-25)+15+x=50
(-10)+x=50
x=50-(-10)
x=50+10
x=60
b)(-25)+15+x=-35
(-10)+x=-35
x=(-35)-(-10)
x=(-35)+10
x=-25
c)(-25)+15+x=-10
(-10)+x=-10
x=-10-(-10)
x=-10+10
x=0
x-(17-8) = 5+(10-3x)
x-9=5+10-3x
x+3x=5+10+9
x+3x=24
4x=24
x=24/4
x=6
vậy x=6
|x+1|=x+1 hoac |x+1|=-(x+1) Voi |x+1|=x+1 ta co:|x+1|=a=>x+1=a=>x=a-1 Voi |x+1|=-(x+1) ta co:|x+1|=a=>-(x+1)=a=>-x-1=a=>-x=a+1=>-(-x)=-(a+1)=>x=-a-1 Vay x=a-1 hoac x=-a-1 nho ****
a) -(x-6)=18
-x+6=18
-x=12
a) -18-(x-6)=0
x-6=(-18)-0
x-6=-18
x = (-18)+6
x = -12
b) 29-(10+29)=x-(27-9)
29-39 = x-18
-10 =x-18
x-18=-10
x = (-10)+18
x = 8
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