Tính bằng cách thuận tiện nhất:
7/19 x1/3 + 7/19 x 2/3
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\(\dfrac{3}{11}\text{×}\dfrac{7}{19}+\dfrac{3}{11}\text{×}\dfrac{10}{19}+\dfrac{3}{11}\text{×}\dfrac{1}{19}=\dfrac{3}{11}\text{×}\left(\dfrac{7}{19}+\dfrac{10}{19}+\dfrac{2}{19}\right)=\dfrac{3}{11}\text{×}1=\dfrac{3}{11}\)
a) \(19\times\left(52+38\right)-9\times\left(52+38\right)=\)
\(=\) \(19\times90-9\times90\)
\(=90\times\left(19-9\right)\)
\(=90\times10\)
\(=900\)
b) \(\dfrac{2}{5}\div\dfrac{3}{7}\times\dfrac{3}{7}\div\dfrac{2}{5}+2019=\)
\(=\left(\dfrac{2}{5}\div\dfrac{2}{5}\right)\times\left(\dfrac{3}{7}\div\dfrac{3}{7}\right)+2019\)
\(=1\times1+2019\)
\(=2019\)
19/37+1-19/37
=(19/37-19/37)+1
=0+1
=1
9/8-(17/7-3/7)+7/8
=(9/8+7/8)-(17/7-3/7)
=2-2
=0
1/2+3/4+1/2
=(1/2+1/2)+3/4
=1+3/4
=7/4
`( 9 xx 6 xx 5 xx 7 )/( 19 xx 7 xx 2 xx 3 )`
`= ( 9 xx 2 xx 3 xx 7 xx 5 )/( 19 xx 7 xx 2 xx 3 )`
`= (9xx5)/19`
`= 45/19`
\(\dfrac{7}{19}\times\dfrac{1}{3}+\dfrac{7}{13}\times\dfrac{2}{3}\)
\(=\dfrac{7}{19}\times\left(\dfrac{1}{3}+\dfrac{2}{3}\right)\)
\(=\dfrac{7}{19}\times1\)
\(=\dfrac{7}{19}\)