\(3\frac{1}{2}x27\frac{27}{46}x\frac{1}{17}x2\frac{4}{9}=\)?
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\(3\frac{1}{11}\times27\frac{27}{4}\times1\frac{6}{17}\times2\frac{4}{9}\)
\(=\frac{34}{11}\times\frac{135}{4}\times\frac{23}{17}\times\frac{22}{9}\)
\(=\frac{17\times2\times9\times3\times3\times23\times11\times2}{11\times2\times2\times17\times3\times3}\)
\(=9\times23\)
\(=207\)
a,(5/8/17+-4/17):x+33/182=4/11
=5/4/17:x+33/182=4/11
5/4/17:x=4/11-33/182
5/4/17:x=365/2002
x=5/4/17:365/2002
x=28/4438/6205
b,-1/5/27-(3x-7/9)^3=-24/27
(3x-7/9)^3=-1/5/27--24/27
(3x-7/9)^3=-8/27
(3x-7/9)^3=(-2/3)^3
3x-7/9=-2/3
3x=-2/3+7/9
3x=1/9
x=1/9:3
x=1/27
a)\(\frac{-5}{13}+\left(\frac{3}{5}+\frac{3}{13}-\frac{4}{10}\right)=\frac{-5}{13}-\frac{3}{5}-\frac{3}{13}+\frac{4}{10}=\left(\frac{-5}{13}-\frac{3}{13}\right)+\frac{4}{10}-\frac{3}{5}=\frac{-5-3}{13}+\left(\frac{4}{10}-\frac{6}{10}\right)=\frac{-8}{13}+\frac{-2}{10}=\frac{-80}{130}+\frac{-26}{130}=\frac{-106}{130}=\frac{-53}{65}\)
\(=\frac{7}{2}x\frac{1269}{46}x\frac{1}{17}x\frac{22}{9}=\frac{7x1269x22}{2x46x17x9}=\frac{10857}{782}\)