3x/5+3(x/10)+1=84
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1) Ta có: \(5\left(x-3\right)\left(x-7\right)-\left(5x+1\right)\left(x-2\right)=-8\)
\(\Leftrightarrow5\left(x^2-10x+21\right)-\left(5x^2-10x+x-2\right)=-8\)
\(\Leftrightarrow5x^2-50x+105-5x^2+9x+2+8=0\)
\(\Leftrightarrow-41x=-115\)
hay \(x=\dfrac{115}{41}\)
2) Ta có: \(x\left(x+1\right)\left(x+2\right)-\left(x+4\right)\left(3x-5\right)=84-5x\)
\(\Leftrightarrow x\left(x^2+3x+2\right)-\left(3x^2+7x-20\right)=84-5x\)
\(\Leftrightarrow x^3+3x^2+2x-3x^2-7x+20-84+5x=0\)
\(\Leftrightarrow x^3=64\)
hay x=4
3) Ta có: \(\left(9x^2-5\right)\left(x+3\right)-3x^2\left(3x+9\right)=\left(x-5\right)\left(x+4\right)-x\left(x-11\right)\)
\(\Leftrightarrow9x^3+27x^2-5x-15-9x^3-27x^2=x^2-x-20-x^2+11x\)
\(\Leftrightarrow-5x-15=10x-20\)
\(\Leftrightarrow-5x-10x=-20+15\)
\(\Leftrightarrow x=\dfrac{-5}{-15}=\dfrac{1}{3}\)
a: =>-3x=1/21*84/5=4/5
=>x=-4/5:3=-4/15
b: =>-1/6x=-3/4-1/5=-19/20
=>x=19/20:1/6=19/20*6=57/10
up từng bài thôi,nhiều thế ko thánh nào làm cho đâu.thách nhau ak
Bài 3:
a: \(A=\dfrac{x+5\sqrt{x}-10\sqrt{x}-5\sqrt{x}+25}{x-25}\)
\(=\dfrac{x-10\sqrt{x}+25}{x-25}=\dfrac{\sqrt{x}-5}{\sqrt{x}+5}\)
b: \(B=\dfrac{x-3\sqrt{x}+2x+6\sqrt{x}-3x-9}{x-9}\)
\(=\dfrac{3\left(\sqrt{x}-3\right)}{x-9}=\dfrac{3}{\sqrt{x}+3}\)
\(3^{\frac{x}{5}}+3^{\frac{x}{10}+1}=84\)
<=> \(\left(3^{\frac{x}{10}}\right)^2+3.3^{\frac{x}{10}}-84=0\)( phương trình bậc 2 ẩn 3^(x/10))
<=> \(\orbr{\begin{cases}3^{\frac{x}{10}}=\frac{-3+\sqrt{345}}{2}\\3^{\frac{x}{10}}=\frac{-3-\sqrt{345}}{2}\left(loai\right)\end{cases}}\)
<=> \(\frac{x}{10}=log_3\left(\frac{-3+\sqrt{345}}{2}\right)\)
<=> \(x=10.log_3\left(\frac{-3+\sqrt{345}}{2}\right)\)