câu 1 : thực hiện phép tính :
a. 3x^2.(2x^2 - 3yz +x^3 )
b. (24x^5 - 12x^4 + 6x^2 ) . 6x^2
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a: \(=4x^4y+6x^2y^2z-2x^5y\)
b: \(=\dfrac{24x^5}{6x^2}-\dfrac{12x^4}{6x^2}+\dfrac{6x^2}{6x^2}=4x^3-2x^2+1\)
c: \(=\dfrac{\left(2x-1\right)^2}{2x-1}=2x-1\)
d: \(=\dfrac{\left(x+5\right)\left(x^2-1\right)}{x+5}=x^2-1\)
a: =x^4-3x^5+4x^8
b: =2x^3+2x^2+4x
c: =4x^2+8x-5
d: =2x+3x^2+7x^4
a: =3x^3-15x^2+21x
b: =-x^3+6x^2+5x-4x^2-24x-20
=-x^3+2x^2-19x-20
c: =9x^2+15x-3x-5-7x^2-14
=2x^2+12x-19
d: =10x^2-4x+2/3
a. \(3x\left(2x+1\right)=6x^2+3x\)
b. \(\left(12x^3-18x^2+6x\right):6x=2x^2-3x+1\)
c. \(\dfrac{7x+6}{5x-1}+\dfrac{8x-9}{5x-1}=\dfrac{15x-3}{5x-1}=\dfrac{3\left(5x-1\right)}{5x-1}=3\)
a,
$xy^2+x^2y+(-2xy^2)=xy^2-2xy^2+x^2y=-xy^2+x^2y$
b,
$12x^2y^3z^4+(-7x^2y^3z^4)=12x^2y^3z^4-7x^2y^3z^4=5x^2y^3z^4$
c,
$-6xy^3-(-6xy^3)+6x^3=-6xy^3+6xy^3+6x^3=0+6x^3=6x^3$
d,
$\frac{-x^2}{2}+\frac{7}{2}x^2+x=(\frac{7}{2}-\frac{1}{2})x^2+x$
$=3x^2+x$
e,
$2x^3+3x^3-\frac{1}{3}x^3=(2+3-\frac{1}{3})x^3=\frac{14}{3}x^3$
f,
$5xy^2+\frac{1}{2}xy^2+\frac{1}{4}xy^2=(5+\frac{1}{2}+\frac{1}{4})xy^2$
$=\frac{23}{4}xy^2$
1. Ta có : 2x4 - 3x3 - 3x2 + 6x - 2
= 2x4 - 2x3 - x3 + x2 - 4x2 + 4x + 2x - 2
= 2x3( x - 1 ) - x2( x - 1 ) - 4x( x - 1 ) + 2( x - 1 )
= ( x - 1 )( 2x3 - x2 - 4x + 2 )
= ( x - 1 )[ x2( 2x - 1 ) - 2( 2x - 1 ) ]
= ( x - 1 )( 2x - 1 )( x2 - 2 )
=> ( 2x4 - 3x3 - 3x2 + 6x - 2 ) : ( x2 - 2 ) = ( x - 1 )( 2x - 1 ) = 2x2 - 3x + 1
2. \(\left(15x^4y^6-12x^3y^4-18x^2y^3\right)\div\left(-6x^2y^2\right)\)
\(=\frac{15x^4y^6}{-6x^2y^2}-\frac{12x^3y^4}{-6x^2y^2}-\frac{18x^2y^3}{-6x^2y^2}\)
\(=-\frac{5}{2}x^2y^4+2xy^2+3y\)
a) 3x2 .(2x2 - 3yz + x3)= 6x4 - 6x2yz +3x5
b)(24x5 - 12x4 + 6x2 ).6x2 = 144x7 - 72x6 +36x4
a) 3x2 . (2x2 - 3yz + x3)
= 3x2 . 2x2 + 3x2 . (- 3yz) + 3x2 . x3
= 6x4 + (-9x2yz) + 3x5
= 6x4 - 9x2yz + 3x5