A: 35x12-15x28+2323/4949-23/49+2010
B: 25%x4/5+3/5-0,8+2010
mọi người giúp tôi nha !!!
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Ta có:
=35x12-15x28+23/49-23/49+2010
=420-420+0+2010
=0+2010
=2010
chúc bạn học tốt
Câu này dễ mà
\(=35.12-15.28+\frac{23}{49}-\frac{23}{49}+2010\)
\(=\left(420-420\right)+\left(\frac{23}{49}-\frac{23}{49}\right)+2010\)
\(=0+0+2010\)
\(=2010\)
35 x 12 - 15 x 28 + \(\frac{2323}{4949}-\frac{23}{49}\)+ 2010
= (420 - 420 )+ \(\left(\frac{23}{49}-\frac{23}{49}\right)\)+ 2010
= 0 + 0 + 2010 = 2010 .
35 x 12 -15 x28+2323/4949-23/49+2010
=35x12-15x28+23/49-23/49+2010
=420-420+0+2010
=0+0+2010
=2010
35 x 12 - 15 x 28 + \(\frac{23}{49}\)- \(\frac{23}{49}\)+ 2017
= 35 x 12 - 15 x 28 + 0 + 2017
= 35 x 12 - 15 x 28 + 2017
= 420 - 420 + 2017
= 0 + 2017
= 2017
a)\(\frac{23.5^2.7^2.3^7}{49.5^3.3^2.11}=\frac{23.5^2.7^2.3^7}{7^2.5^3.3^2.11}=\frac{23.3^5}{5.11}=\frac{23.243}{5.11}=\)\(\frac{5589}{55}\)
b) \(\frac{9^{14}.25^5.8^7}{18^{12}.6^{25}.3^{243}}=\frac{3^{28}.5^{10}.2^{21}}{\left(3^2.2\right)^{12}.\left(2.3\right)^{25}.3^{243}}=\frac{3^{28}.5^{10}.2^{21}}{3^{24}.2^{12}.2^{25}.3^{25}.3^{243}}=\frac{3^{28}.5^{10}.2^{21}}{3^{292}.2^{37}}=\frac{5^{10}}{3^{264}.2^{16}}\)
\(\frac{25^4\cdot7^2+5^8\cdot49}{5^8\cdot2^3-25^4}=\frac{5^8\cdot7^2+5^8\cdot7^2}{5^8\cdot2^3-5^8}=\frac{5^8\cdot7^2\cdot\left(1+1\right)}{5^8\cdot\left(2^3-1\right)}=\frac{2\cdot5^8\cdot7^2}{5^8\cdot7}=2\cdot7=14\)