2 x 2 x 3 x 6 x 2 x 2 + 2 + 9 + 9=???
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
A
Rút gọn:
A=(x+3+2.(x^-9)^1/2):(2x-6+(x^2-9)^1/2
B=(x^2+5x+6+x.(9-x^2)^1/2):(3x-x^2+(x+2).(9-x^2)^1/2
0
T
Rút gọn:
A=(x+3+2.(x^-9)^1/2)/(2x-6+(x^2-9)^1/2
B=(x^2+5x+6+x.(9-x^2)^1/2)/(3x-x^2+(x+2).(9-x^2)^1/2
0
31 tháng 10 2018
| 9 x 1 = 9 | 9 x 2 = 18 | 9 x 3 = 27 | 9 x 4 = 36 |
| 1 x 9 = 9 | 2 x 9 = 18 | 3 x 9 = 27 | 4 x 9 = 36 |
| 9 x 5 = 45 | 9 x 6 = 54 | 9 x 7 = 63 | 9 x 8 = 72 |
| 5 x 9 = 45 | 6 x 9 = 54 | 7 x 9 = 63 | 8 x 9 =72 |
CM
13 tháng 4 2019
Học sinh nhẩm và ghi kết quả như sau:
3 x 4 = 12 2 x 6 = 12 4 x 3 = 12 5 x 6 = 30
3 x 7 = 21 2 x 8 = 16 4 x 7 = 28 5 x 4 = 20
3 x 5 = 15 2 x 4 = 8 4 x 9 = 36 5 x 7 = 35
3 x 8 = 24 2 x 9 = 18 4 x 4 = 16 5 x 9 = 45
6 tháng 9 2021
3 x4 = 12
3 x7 = 21
3 x5 = 15
3 x8 =24
2 x 6= 12
2 x8 = 16
2 x4 =8
2 x9 =18
4 x3 =12
4 x7 =28
4 x9 =36
4 x4 =16
5 x6 =30
5 x4 =20
5 x7 =35
5 x9 =45
NQ
1
Y
25 tháng 6 2023
\(A=\left(\dfrac{3x-x^2}{9-x^2}-1\right):\left(\dfrac{9-x^2}{x^2+x-6}+\dfrac{x-3}{2-x}-\dfrac{x+2}{x+3}\right)\left(dk:x\ne\pm3,x\ne2\right)\)
\(=\dfrac{3x-x^2-9+x^2}{9-x^2}:\left(\dfrac{9-x^2}{\left(x-2\right)\left(x+3\right)}-\dfrac{x-3}{x-2}-\dfrac{x+2}{x+3}\right)\)
\(=\dfrac{3x-9}{9-x^2}:\dfrac{9-x^2-\left(x-3\right)\left(x+3\right)-\left(x+2\right)\left(x-2\right)}{\left(x-2\right)\left(x+3\right)}\)
\(=-\dfrac{3\left(x-3\right)}{\left(x-3\right)\left(x+3\right)}.\dfrac{\left(x-2\right)\left(x+3\right)}{9-x^2-\left(x^2-9\right)-\left(x^2-4\right)}\)
\(=-\dfrac{3}{x+3}.\dfrac{\left(x-2\right)\left(x+3\right)}{9-x^2-x^2+9-x^2+4}\)
\(=\dfrac{-3\left(x-2\right)}{22-3x^2}\)
\(=\dfrac{-3x+6}{22-3x^2}\)
Vậy \(A=\dfrac{-3x+6}{22-3x^2}\) với \(x\ne\pm3,x\ne2\)
4 tháng 7 2021
Ta có: \(\left(\dfrac{x^2-3x}{x^2-9}-1\right):\left(\dfrac{9-x^2}{x^2+x-6}-\dfrac{x-3}{2-x}+\dfrac{x-2}{x+3}\right)\)
\(=\left(\dfrac{x\left(x-3\right)}{\left(x-3\right)\left(x+3\right)}-1\right):\left(\dfrac{9-x^2+x^2-9+\left(x-2\right)^2}{\left(x-2\right)\left(x+3\right)}\right)\)
\(=\left(\dfrac{x}{x+3}-1\right):\dfrac{x-2}{x+3}\)
\(=\dfrac{x-x-3}{x+3}\cdot\dfrac{x+3}{x-2}\)
\(=\dfrac{-3}{x-2}\)
H
4 tháng 7 2021
Điều kiện : x ≠ 2 ; x ≠ 3 ; x ≠ - 3
\(\left(\dfrac{x\left(x-3\right)}{\left(x+3\right)\left(x-3\right)}-1\right):\left(\dfrac{\left(3-x\right)\left(x+3\right)}{\left(x-2\right)\left(x+3\right)}-\dfrac{x-3}{2-x}+\dfrac{x-2}{x+3}\right)\)
\(=\left(\dfrac{x}{x+3}-1\right):\left(\dfrac{9-x^2+\left(x-3\right)\left(x+3\right)+\left(x-2\right)^2}{\left(x-2\right)\left(x+3\right)}\right)\)
\(=\dfrac{x-x-3}{x+3}:\dfrac{9-x^2+x^2-9+\left(x-2\right)^2}{\left(x-2\right)\left(x+3\right)}\)
\(=\dfrac{-3}{x+3}:\dfrac{x-2}{\left(x+3\right)}\)
\(=\dfrac{-3}{x-2}\)
2x2x3x6x2x2+2+2+9+9=308
308 nhớ tck cho me nhaaaaaa