rút gọn biểu thức:
\(\left(x+3\right)^3-2\left(x+2\right)^2\)
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\(=\left(x-3\right)\left(x^2+1-x^2+1\right)=2\left(x-3\right)\)
\(\left(3x-5\right)^2+\left(x+2\right)^2+x\left(3-4x\right)\)
\(=9x^2-30x+25+x^2+4x+4+3x-4x^2\)
\(=6x^2-23x+29\)
\(=\left(x-1\right)^2-\left(x+2\right)\left[2\left(x-2\right)+3\left(x+2\right)^2\right]\)
\(=x^2-2x+1-\left(x+2\right)\left[2x-4+3\left(x^2+4x+4\right)\right]\)
\(=x^2-2x+1-\left(x+2\right)\left(3x^2+14x+8\right)\)
\(=x^2-2x+1-\left(3x^3+6x^2+14x^2+28x+8x+16\right)\)
\(=-3x^3-21x^2-38x-15\)
\(\left(x-2\right)\left(x^2+2x+4\right)-\left(x-3\right)^3-\left(x-2\right)^3\)
\(=x^3+2x^2+4x-2x^2-4x-8\) \(-\left(x^3-3x^2.3+3x.3^2-27\right)-\)-\(\left(x^3-3.x^2.2+3.x.2^2-8\right)\)
\(=x^3-8\) \(-x^3+9x^2-27x+27-x^3+6x^2-12x+8\)
\(=-x^3+15x^2-39x+27\)
học tốt
a: \(\left(x-2y\right)^2+\left(x-\dfrac{1}{2}y\right)\left(x+\dfrac{1}{2}y\right)\)
\(=x^2-4xy+4y^2+x^2-\dfrac{1}{4}y^2\)
\(=2x^2-4xy+\dfrac{15}{4}y^2\)
b: \(\left(x-2\right)^2+\left(x+3\right)^2-2\left(x-1\right)\left(x+1\right)\)
\(=x^2-4x+4+x^2+6x+9-2\left(x^2-1\right)\)
\(=2x^2+2x+13-2x^2+2\)
=2x+15
a) \(=x^2-4xy+4y^2+x^2-\dfrac{1}{4}y^2=2x^2-4xy+\dfrac{15}{4}y^2\)
b) \(=x^2-4x+4+x^2+6x+9-2x^2+2\)
\(=2x+15\)
Bài làm:
Ta có: \(\left(2x+5\right)\left(x-2\right)-3\left(x+2\right)^2+\left(x+1\right)^2\)
\(=2x^2+x-10-3\left(x^2+4x+4\right)+x^2+2x+1\)
\(=3x^2+3x-9-3x^2-12x-12\)
\(=-9x-21\)
\(\left(2x+5\right)\left(x-2\right)-3\left(x+2\right)^2+\left(x+1\right)^2\)
\(=2x\left(x-2\right)+5\left(x-2\right)-3\left(x^2+4x+4\right)+\left(x^2+2x+1\right)\)
\(=2x^2-4x+5x-10-3x^2-12x-12+x^2+2x+1\)
\(=\left(2x^2-3x^2+x^2\right)+\left(5x-4x-12x+2x\right)-\left(10+12-1\right)\)
\(=0+x-10x-21=-9x-21\)
\(\left(x+3\right)^3-2\left(x+2\right)^2=\left(x+2\right)^2\left(x+3-2\right)\)\(=\left(x+2\right)^2\left(x+1\right)\)
\(\left(x+3\right)^3-2\left(x+2\right)^2\)
\(=x^3+9x^2+27x+9-2\left(x^2+4x+4\right)\)
\(=x^3+9x^2+27x+9-2x^2-8x-8\)
\(=x^3+7x^2+19x+1\)