Tìm X biết X x 52 + X x 48 = 4200
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Ta có:
x*62+x*48=4200.
x*(62+48)=4200.
x*110=4200.
x*11=420.
x=420/11.
Vậy x=420/11.
X x 62 +X x 48 = 4200
=> X x (62+48)=4200
=> X x 110=4200
=> X=4200:110
=> X=\(\frac{420}{11}\)
Xx62+Xx48 = 4200
Xx(62+48)=4200
Xx110=4200
X=4200:110
X=38(18)
X×62+X×48=4200
\(x\times\left(62+48\right)=4200\)
\(x\times110=4200\)
\(x=4200:110\)
\(x=\dfrac{420}{11}\)
X x 62 + X x 48= 4200
X x(62 + 48)= 4200
X x 110= 4200
X = 4200 : 110
X = 4200/ 110= 420/ 11
=> x . ( 62 + 38 ) = 4200
=> x . 100 = 4200
=> x = 4200 : 100
=> x = 42
\(x\times62+x\times38=4200\)
\(x\times\left(62+38\right)=4200\)
\(x\times100=4200\)
\(x=4200:100\)
\(x=42\)
\(a.16307:y=45\left(dư\text{ }17\right)\)\(\Leftrightarrow45\text{×}y+17=16307\)
\(45\text{×}y=16307-17\)
\(45\text{×}y=16290\)
\(y=16290:45\)
\(y=362\)
\(b.y\text{×}52+y\text{×}48=36700\)
\(y\text{×}\left(52+48\right)=36700\)
\(y\text{×}100=36700\)
\(y=36700:100\)
\(y=367\)
a) 16307= 45*y+17 -> y=(16307-17)/45= 362
b) y*(52+48)= 36700 -> y=36700/100= 367
\(y\times48+y\times52=201400\)
\(y\times(48+52)=201400\)
\(y\times100=201400\)
\(y=201400:100\)
\(y=2014\)
X x 52 + X x 48 = 4200
=>Xx(52+48)=4200
Xx100=4200
X=4200:100
X=42
Vậy X=42
X x 52 + X x 48 = 4200
X x ( 52 + 48 ) = 4200
X x 100 = 4200
X = 4200 : 100
X = 42