THỰC HIỆN PHÉP TÍNH
\(\frac{2^{30}.9^8}{6^2.8^6}\)
JUP MIK GÁP MN
K
Khách
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25 tháng 12 2021
Kết quả nè bạn ơi;
A; 3/4 + 2/5=23/20
B;7/4 - 1/2=5/4
C;4/9 x 6/8=24/72
D;14/5 : 7/8=112/35
AK
30 tháng 4 2018
\(\frac{8}{9}-\frac{1}{72}-\frac{1}{56}-\frac{1}{30}-\frac{1}{20}-\frac{1}{12}-\frac{1}{6}-\frac{1}{2}\)
\(=\frac{8}{9}-\left(\frac{1}{72}+\frac{1}{56}+\frac{1}{42}+\frac{1}{30}+\frac{1}{20}+\frac{1}{12}+\frac{1}{6}+\frac{1}{2}\right)\)
\(=\frac{8}{9}-\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}\right)\)
\(=\frac{8}{9}-\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{8.9}\right)\)
\(=\frac{8}{9}-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{8}-\frac{1}{9}\right)\)
\(=\frac{8}{9}-\left(1-\frac{1}{9}\right)\)
\(=\frac{8}{9}-\frac{8}{9}\)
\(=0\)
Chúc bạn học tốt !!!!
XO
13 tháng 9 2020
\(\frac{9}{8}-\frac{1}{2}-\frac{1}{6}-\frac{1}{12}-...-\frac{1}{72}=\frac{9}{8}-\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{72}\right)\)
\(=\frac{9}{8}-\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{8.9}\right)\)
\(=\frac{9}{8}-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{8}-\frac{1}{9}\right)\)
\(=\frac{9}{8}-\left(1-\frac{1}{9}\right)=\frac{9}{8}-\frac{8}{9}=\frac{17}{72}\)
28 tháng 2 2022
a: \(=\dfrac{-3^4\cdot2^8}{2^2\cdot2^2\cdot3^2}=-3^2\cdot2^2=-6^2=-36\)
b: \(=\dfrac{3^6\cdot2^{15}}{3^6\cdot2^6\cdot2^{15}}=\dfrac{1}{2^6}=\dfrac{1}{64}\)
c: \(=\left(\dfrac{0.8}{0.4}\right)^5\cdot\dfrac{1}{0.4}=2^5\cdot\dfrac{1}{0.4}=\dfrac{32}{0.4}=80\)
NT
1
25 tháng 6 2021
Ta có: \(\dfrac{8}{9}-\dfrac{1}{72}-\dfrac{1}{56}-\dfrac{1}{42}-\dfrac{1}{30}-\dfrac{1}{20}-\dfrac{1}{12}-\dfrac{1}{6}-\dfrac{1}{2}\)
\(=\dfrac{8}{9}-\left(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{42}+\dfrac{1}{56}+\dfrac{1}{72}\right)\)
\(=\dfrac{8}{9}-\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{9}\right)\)
\(=\dfrac{8}{9}-\left(1-\dfrac{1}{9}\right)\)
\(=\dfrac{8}{9}-\dfrac{8}{9}=0\)
HK
15 tháng 3 2020
Tính nhanh:
912 + [88 + (-453) + (-547)]
= 912 + 88 - 453 - 547
= (912 + 88) - (453 + 547)
= 1000 - 1000
= 0
Thực hiện các phép tính sau:
6-8 = 6 + (-8) = -2
3-(-9) = 3 + 9 = 12
(-5)-10 = (-5) + (-10) = -15
0-7 = -7
4-0 = 4
(-2)-(-10) = (-2) + 10 = 8
Tính:
-2+(-6)+7- 3 = -4
-5-7-3+7 = -8
(-6)-4+5-7+12 = 0
2-(-8)+10-30 = -10
Bỏ dấu ngoặc rồi tính:
a) (4+32+6)+(10-36-6)
= 4 + 32 + 6 + 10 - 36 - 6
= (4 + 32 - 36) + (6 - 6) + 10
= 0 + 0 + 10
= 10
b) (77+22+-65)-(67+12-75)
= 77 + 22 - 65 - 67 - 12 + 75
= (77 - 67) + (22 - 12) - (65 - 75)
= 10 + 10 - (-10)
= 30
c)-(-21+43+7)-(11-53-17).
= 21 - 43 - 7 - 11 + 53 + 17
= (21 - 11) - (43 - 53) - (7 - 17)
= 10 - (-10) - (-10)
= 30
Tham khảo nha!!!
MH
18 tháng 9 2021
\(\dfrac{-6}{25}+\left|\dfrac{-4}{5}\right|-\left|\dfrac{2}{25}\right|\)
\(=\dfrac{-6}{25}+\dfrac{4}{5}-\dfrac{2}{25}\)
\(=\dfrac{-6}{25}+\dfrac{20}{25}-\dfrac{2}{25}\)
\(=\dfrac{12}{25}\)
25 tháng 12 2021
a)\(\frac{3}{4}+\frac{2}{5}=\frac{15}{20}+\frac{8}{20}=\frac{23}{20}\)
b) \(\frac{7}{4}-\frac{1}{2}=\frac{14}{8}-\frac{4}{8}=\frac{10}{8}=\frac{5}{4}\)
c) \(\frac{4}{9}.\frac{6}{8}=\frac{24}{72}=\frac{1}{3}\)
d) \(\frac{14}{5}:\frac{7}{8}=\frac{14}{5}.\frac{8}{7}=\frac{72}{35}\)
6 tháng 6 2020
a, \(\frac{2}{5}.\frac{1}{3}-\frac{2}{15}:\frac{1}{5}+\frac{3}{5}.\frac{1}{3}\)
\(=\frac{1}{3}.\left(\frac{2}{5}+\frac{3}{5}\right)-\frac{2}{15}.5\)
\(=\frac{1}{3}.1-\frac{2}{3}\)
\(=\frac{1}{3}-\frac{2}{3}\)
\(=\frac{-1}{3}\)
b, \(\left(6-2\frac{4}{5}\right).3\frac{1}{8}+1\frac{3}{8}:\frac{1}{4}\)
\(=\left(6-\frac{14}{5}\right).\frac{25}{8}+\frac{11}{8}.4\)
\(=\frac{16}{5}.\frac{25}{8}+\frac{11}{2}\)
\(=10+\frac{11}{2}\)
\(=\frac{31}{2}\)
6 tháng 6 2020
1/3×(3/5+2/5)-2/15×1/5
1/3×1-2/15×1/5
1/3-2/15×1/5
1/3-2/75
25/75-2/75
23/75
(6-14/5)×25/8-11/8:4/1
16/5×25/8-11/8:4/1
10/1-11/8:4/1
10/1-11/8×1/4
10/1-11/32
320/32-11/32
309/32
\(\frac{2^{30}.9^8}{6^2.8^6}\) =\(\frac{2^8.9^8.2^{32}}{\left(2.3\right)^2.\left(2^3\right)^6}\) =\(\frac{2^{10}.\left(3^2\right)^8}{3^2}\) =\(2^{10}.9^7\)