1)Cho góc \(\alpha\) thõa mãn \(tan\alpha=-\frac{4}{3}\) và \(\frac{\pi}{2} \alpha \pi\) . Tính P = \(\frac{sin^2\alpha-cos\alpha}{sin\alpha-cos^2\alpha}\)
2)Cho góc \(\alpha\) thõa mãn \(tan\alpha=5\) . Tính P =...
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1)Cho góc \(\alpha\) thõa mãn \(tan\alpha=-\frac{4}{3}\) và \(\frac{\pi}{2}< \alpha< \pi\) . Tính P = \(\frac{sin^2\alpha-cos\alpha}{sin\alpha-cos^2\alpha}\)
2)Cho góc \(\alpha\) thõa mãn \(tan\alpha=5\) . Tính P = \(sin^4\alpha-cos^4\alpha\)
Câu 1:
\(\frac{\pi}{2}< a< \pi\Rightarrow\left\{{}\begin{matrix}sina>0\\cosa< 0\end{matrix}\right.\)
Ta có: \(\frac{1}{cos^2a}=1+tan^2a\Rightarrow cos^2a=\frac{1}{1+tan^2a}\Rightarrow cosa=\frac{-1}{\sqrt{1+tan^2a}}=-\frac{3}{5}\)
\(\Rightarrow sina=cosa.tana=\frac{4}{5}\)
\(\Rightarrow P=\frac{\frac{16}{25}+\frac{3}{5}}{\frac{4}{5}-\frac{9}{25}}=\frac{31}{11}\)
Câu 2:
\(P=sin^4a-cos^4a=\left(sin^2a+cos^2a\right)\left(sin^2a-cos^2a\right)=sin^2a-cos^2a\)
\(P=1-cos^2a-cos^2a=1-2cos^2a\)
Theo cmt ta có \(cos^2a=\frac{1}{1+tan^2a}\Rightarrow P=1-\frac{2}{1+tan^2a}=\frac{12}{13}\)