A=3/11.4/13+(3/13.4/11-1/13)
giúp ik
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Ta có: \(\dfrac{8.5-8.2}{16}=\dfrac{8\left(5-2\right)}{16}=\dfrac{8.3}{16}=\dfrac{3}{2}\)
\(\dfrac{11.4-11}{2-13}=\dfrac{11\left(4-1\right)}{-11}=\dfrac{11.3}{-11}=-3\)
\(A=\frac{2}{13}.\frac{5}{9}+\frac{2}{13}.\frac{4}{9}+\frac{11}{13}=\frac{2}{13}.\left(\frac{5}{9}+\frac{4}{9}\right)+\frac{11}{3}\)
\(=\frac{2}{13}.1+\frac{11}{13}\)
\(=\frac{2}{13}+\frac{11}{13}=1\)
\(A=\frac{2}{13}\cdot\frac{5}{9}+\frac{2}{13}\cdot\frac{4}{9}+\frac{11}{13}\)
\(A=\frac{2}{13}\left(\frac{5}{9}+\frac{4}{9}\right)+\frac{11}{13}\)
\(A=\frac{2}{13}\cdot1+\frac{11}{13}\)
\(A=\frac{2}{13}+\frac{11}{13}\)
\(A=\frac{13}{13}=1\)
\(\dfrac{-63}{72}=\dfrac{-7}{8}\)
\(\dfrac{20}{-140}=\dfrac{-1}{7}\)
\(\dfrac{3.10}{5.24}=\dfrac{30}{120}=\dfrac{1}{4}\)
\(\dfrac{3.7.11}{22.9}=\dfrac{231}{198}=\dfrac{7}{6}\)
\(\dfrac{8.5-8.2}{16}=\dfrac{24}{16}=\dfrac{3}{2}\)
\(\dfrac{11.4-11}{2-13}=\dfrac{33}{-11}=-3\)
a. \(\dfrac{8,5-8,2}{16}=\dfrac{0,3}{16}=\dfrac{3}{160}\)
b. \(\dfrac{2\cdot14}{7\cdot8}=\dfrac{1\cdot2}{1\cdot4}=\dfrac{2}{4}=\dfrac{1}{2}\)
c. \(\dfrac{11\cdot4-11}{2-13}=\dfrac{11\left(4-1\right)}{-11}=\dfrac{1\cdot3}{-1}=-3\)
d. \(\dfrac{49+7\cdot49}{49}=\dfrac{49\cdot\left(1+7\right)}{49}=\dfrac{8}{1}=8\)