bài tập : tính
3/7 nhân 56/63+3/7 nhân 17/63
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a)\(8-\frac{3}{5}=\frac{40}{5}-\frac{3}{5}=\frac{37}{5}\)
b)\(\frac{24}{15}\times\frac{56}{72}\times\frac{10}{14}=\frac{13440}{15120}=\frac{8}{9}\)
c)\(\frac{32}{48}\times\frac{35}{21}\times\frac{63}{14}\times\frac{9}{30}=\frac{2}{3}\times\frac{5}{3}\times\frac{9}{2}\times\frac{3}{10}=\frac{270}{180}=\frac{3}{2}\)
d)\(7-\frac{72}{48}\times\frac{56}{60}-3=7-\frac{3}{2}\times\frac{14}{15}-3\)
\(=7-\frac{7}{5}-3\)
\(=\frac{35}{5}-\frac{7}{5}-\frac{15}{5}\)
\(=\frac{13}{5}\)
#H
(Sai thì sửa)
NÀY HẢ:
\(17\cdot36+17\cdot63+17\)
\(=17\cdot36+17\cdot63+17\cdot1\)
\(=17\cdot\left(36+63+1\right)=17\cdot100=1700\)
K MK NHA.
\(\frac{24}{36}:\frac{8}{9}=\frac{24}{36}\cdot\frac{9}{8}=\frac{24\cdot9}{36\cdot8}=\frac{216}{288}=\frac{3}{4}\)
\(\frac{32}{45}-\frac{7}{30}=\frac{64}{90}-\frac{21}{90}=\frac{43}{90}\)
\(\frac{3}{10}+\frac{4}{7}+\frac{6}{14}+\frac{4}{20}=\frac{42}{140}+\frac{80}{140}+\frac{60}{140}+\frac{28}{140}=\frac{210}{140}=\frac{3}{2}\)
\(\frac{17}{25}\cdot\frac{11}{28}+\frac{34}{50}\cdot\frac{17}{28}=\frac{187}{700}+\frac{289}{700}=\frac{476}{700}=\frac{17}{25}\)
\(\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+...+\frac{1}{11\cdot12}=\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{11}-\frac{1}{12}=\frac{1}{3}-\frac{1}{12}=\frac{1}{4}\)
\(\frac{3}{7}\cdot\frac{56}{63}+\frac{3}{7}\cdot\frac{17}{63}\)
\(=\frac{3}{7}\cdot(\frac{56}{63}+\frac{17}{63})\)
\(=\frac{3}{7}\cdot\frac{73}{63}=\frac{3\cdot73}{7\cdot63}=....\)
Bạn tự tính nhé
\(\frac{3}{7}\)x \(\frac{56}{63}\) + \(\frac{3}{7}\)x \(\frac{17}{63}\)
= \(\frac{3}{7}\)x \(\left(\frac{56}{63}+\frac{17}{63}\right)\)
= \(\frac{3}{7}\)x \(\frac{73}{63}\)
= \(\frac{73}{147}\)