Tính nhanh
(2+4+6+...+2020) x (182 x 234 -91 x 468)
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26 x 182 + 182 x 47 + 91 x 27 x 2
=26 x 182 + 182 x 47 +(91x2)x27
=26 x 182 + 182 x 47 + 182x27
= 182x(26+47+27)
= 182x100
=18200
a)-(2x + 15 ) + 13 = -234
\(\Leftrightarrow\)-2x-15+13+234=0
\(\Leftrightarrow\)2x=232
\(\Leftrightarrow\)x=116
b)2+4+6+8 +..............+2x=182
\(\Leftrightarrow\)2(1+2+3+4+.....+x) =182
\(\Leftrightarrow\)1+2+3+4+.....+x= 182/2 = 91
\(\Leftrightarrow\)x(x+1)/2 =91
\(\Leftrightarrow\)x(x+1)= 182
\(\Leftrightarrow\)x(x+1) = 13(13+1)
\(\Leftrightarrow\)\(\hept{\begin{cases}x=13\\x+1=13+1\end{cases}}\Leftrightarrow x=13\)
Vậy...
a/ \(x-\dfrac{3}{7}=\dfrac{2}{5}\cdot\dfrac{1}{4}\)
\(x-\dfrac{3}{7}=\dfrac{1}{10}\)
\(x=\dfrac{1}{10}+\dfrac{3}{7}=\dfrac{37}{70}\)
Vậy....
b/ \(x+\dfrac{4}{5}=-\dfrac{5}{12}\cdot\dfrac{3}{25}\)
\(x+\dfrac{4}{5}=-\dfrac{1}{20}\)
\(x=-\dfrac{1}{20}-\dfrac{4}{5}=-\dfrac{17}{20}\)
Vậy....
c/ \(\dfrac{x}{182}=-\dfrac{6}{12}\cdot\dfrac{35}{91}\)
\(\dfrac{x}{182}=-\dfrac{5}{26}\)
\(=>x\cdot26=-5\cdot182\)
\(26x=-910\)
\(x=-910:26=-35\)
Vậy....
a) Ta có: \(x-\dfrac{3}{7}=\dfrac{2}{5}\cdot\dfrac{1}{4}\)
\(\Leftrightarrow x-\dfrac{3}{7}=\dfrac{1}{10}\)
\(\Leftrightarrow x=\dfrac{1}{10}+\dfrac{3}{7}=\dfrac{7}{70}+\dfrac{30}{70}\)
hay \(x=\dfrac{37}{70}\)
Vậy: \(x=\dfrac{37}{70}\)
570-225-167+67=345-167+67
=178+67=245
168x2:6x4=336:6x4=56x4=224
b)468:6+61x2=78+61x2=78+122=200
5625-5000:(726:6-113)=5625-5000:8=5625-625=5000
tick cho minh nha
Trả lời
a)964.3+496.4-496.6
=964.3+[496.(4-6)]
=964.3+(-992)
=2892+(-992)
=1900
b)2019.(2020+1)-2019.2020
=2019.2020.2019-2019.2020
=2019
c)436+324.(234-1)-234.324+324
=436+324.234-324-234.324+324
=436
d)472.(36-1)+35.8
=472.35+35.8
=35.(472+8)
=35.480
=16 800
Ko chắc nha, sai thì cho mk xl vì làm phiền bạn !
b)2019.(2020+1)-2019.2020
=2019.(2020+1-2020)
=2019.1
=2019
\(\frac{328}{435}\cdot\frac{468}{432}\cdot\frac{435}{164}\cdot\frac{432}{984}\cdot\frac{164}{468}\)
\(=\frac{328}{984}\)
\(=\frac{1}{3}\)
(2+4+6+...+2020) x (182 x 234 -91 x 468)
= (2+4+6+...+2020) x (91x2x234 -91 x 234x2)
= (2+4+6+...+2020) x 0
=0