Tính nhanh
( 9x8-12-5x12) x ( 1+2+3+4+5)
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Ta có: ( 9x8-12-5x12) x (1+2+3+4+5)
=( 72-12-60) x ( 1+2+3+4+5)
=(60-60) x (1+2+3+4+5)
=0 x (1+2+3+4+5)
=0
Mọi người tk cho mình nha. Mình cảm ơn trước vậy ^.<
(9 x 8 - 12 - 5 x 12) x (1 + 2 + 3 + 4 + 5)
= (72 - 12 - 60) x (1 + 2 + 3 + 4 + 5)
= ( 60 - 60) x (1 + 2 + 3 + 4 + 5)
= 0 x (1 + 2 + 3 + 4 + 5)
= 0
a) \(\frac{8}{21}+\frac{13}{21}=\frac{8+13}{21}=\frac{21}{21}=1\)
b) \(\frac{5}{6}:\frac{-7}{12}=\frac{5}{6}.\frac{12}{-7}=\frac{10}{-7}\)
c) \(-4\frac{1}{4}-\frac{3}{4}=\frac{-17}{4}-\frac{3}{4}=\frac{-17-3}{4}=\frac{-20}{4}=-5\)
d) \(\frac{7}{9}.\frac{8}{17}+\frac{7}{9}.\frac{15}{17}-\frac{7}{9}.\frac{6}{17}\)
\(=\frac{7}{9}.\left(\frac{8}{17}+\frac{15}{17}-\frac{6}{17}\right)\)
\(=\frac{7}{9}.\frac{17}{17}\)
\(=\frac{7}{9}.1\)
\(=\frac{7}{9}\)
a) \(\frac{8}{21}+\frac{13}{21}=1\)
b) \(\frac{5}{6}\div\frac{-7}{12}=\frac{5}{6}.\frac{-12}{7}=\frac{-10}{7}\)
c) \(-4\frac{1}{4}-\frac{3}{4}=\frac{-17}{4}-\frac{3}{4}=-5\)
d) \(\frac{7}{9}.\frac{8}{17}+\frac{7}{9}.\frac{15}{7}-\frac{7}{9}.\frac{6}{17}=\frac{7}{9}.\left(\frac{8}{17}+\frac{15}{17}-\frac{6}{17}\right)=\frac{7}{9}.1=\frac{7}{9}\)
( 9 x 8 – 12 – 5 x 12 ) x ( 1 + 2 + 3 + 4 + 5 )
= ( 72 – 12 – 60 ) x ( 1 + 2 + 3 + 4 + 5)
= 0 x ( 1 + 2 + 3 + 4 + 5 )
= 0
Đáp án:
( 9 x 8 – 12 – 5 x 12 ) x ( 1 + 2 + 3 + 4 + 5 )
= ( 72 – 12 – 60 ) x ( 1 + 2 + 3 + 4 + 5)
= 0 x ( 1 + 2 + 3 + 4 + 5 )
= 0
a. 4 x 126 x 25
= (4 x 25) x 126
= 100 x 126
= 12600
b. (9 x 8 – 12 – 5 x 12) x ( 1 + 2 + 3 + 4 + 5)
= (72 – 12 – 60) x ( 1 + 2 + 3 + 4 + 5)
= 0 x ( 1 + 2 + 3 + 4 + 5)
= 0
\(1,\frac{2}{3}+\frac{4}{9}+\frac{1}{5}+\frac{2}{15}+\frac{3}{2}-\frac{17}{18}\)
\(< =>\frac{4}{9}+\frac{3}{2}+\left(\frac{2}{3}+\frac{1}{5}+\frac{2}{15}\right)-\frac{17}{18}\)
\(< =>\frac{8}{18}+\frac{27}{18}+\left(\frac{10}{15}+\frac{3}{15}+\frac{2}{15}\right)-\frac{17}{18}\)
\(< =>\frac{35}{18}+1-\frac{17}{18}\)
\(< =>\frac{53}{18}-\frac{17}{18}\)
\(< =>2\)
\(2,\frac{13}{28}\cdot\frac{5}{12}-\frac{5}{28}\cdot\frac{1}{12}\)
\(< =>\left(\frac{13}{28}-\frac{5}{28}\right)\cdot\left(\frac{5}{12}-\frac{1}{12}\right)\)
\(< =>\frac{2}{7}\cdot\frac{1}{3}\)
\(< =>\frac{2}{21}\)
\(3,\frac{19}{4}\cdot\frac{15}{23}-\frac{15}{4}\cdot\frac{7}{23}+\frac{15}{4}\cdot\frac{11}{23}\)
\(< =>\frac{285}{92}-\frac{105}{92}+\frac{165}{92}\)
\(< =>\frac{15}{4}\)
(9x8-12-12x5)x(1+2+3+4+5)
= (72-12-60)x(1+2+3+4+5)
= 0x(1+2+3+4+5)
=0
( 9 x 8 - 12 - 5 x 12 ) x ( 1 + 2 + 3 + 4 + 5 )
= ( 3 x 3 x 4 x 2 - 12 - 5 x 12 ) x ( 1 + 2 + 3 + 4 + 5 )
= ( 6 x 12 - 12 - 5 x 12 ) x ( 1 + 2 + 3 + 4 + 5 )
= { 12 x ( 6 - 5 - 1 ) } x ( 1 + 2 + 3 + 4 + 5 )
= 12 x 0 x ( 1 + 2 + 3 + 4 + 5 )
= 0
k cho mình nha chúc bạn học tốt