Tính hợp lý
A, (-172)+56+(-26)+72
Giúp mk vs mk đag cần Gấp ạ...
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a) Ta có: \(P=\dfrac{a\sqrt{a}-1}{a-\sqrt{a}}-\dfrac{a\sqrt{a}+1}{a+\sqrt{a}}+\left(\sqrt{a}-\dfrac{1}{\sqrt{a}}\right)\left(\dfrac{3\sqrt{a}}{\sqrt{a}-1}-\dfrac{\sqrt{a}+2}{\sqrt{a}+1}\right)\)
\(=\dfrac{\left(\sqrt{a}-1\right)\left(a+\sqrt{a}+1\right)}{\sqrt{a}\left(\sqrt{a}-1\right)}-\dfrac{\left(\sqrt{a}+1\right)\left(a-\sqrt{a}+1\right)}{\sqrt{a}\left(\sqrt{a}+1\right)}+\dfrac{a-1}{\sqrt{a}}\cdot\dfrac{3\sqrt{a}\left(\sqrt{a}+1\right)-\left(\sqrt{a}+2\right)\left(\sqrt{a}-1\right)}{\left(\sqrt{a}-1\right)\left(\sqrt{a}+1\right)}\)
\(=\dfrac{a+\sqrt{a}+1-a+\sqrt{a}-1}{\sqrt{a}}+\dfrac{3a+3\sqrt{a}-\left(a-\sqrt{a}+2\sqrt{a}-2\right)}{\sqrt{a}}\)
\(=2+\dfrac{3a+3\sqrt{a}-a+\sqrt{a}-2\sqrt{a}+2}{\sqrt{a}}\)
\(=\dfrac{2\sqrt{a}+2a+2\sqrt{a}+2}{\sqrt{a}}\)
\(=\dfrac{2\left(a+2\sqrt{a}+1\right)}{\sqrt{a}}\)
\(=\dfrac{2\left(\sqrt{a}+1\right)^2}{\sqrt{a}}\)
b) Ta có: \(P-6=\dfrac{2\left(\sqrt{a}+1\right)^2-6\sqrt{a}}{\sqrt{a}}\)
\(=\dfrac{2a+4\sqrt{a}+2-6\sqrt{a}}{\sqrt{a}}\)
\(=\dfrac{2\left(a-\sqrt{a}+1\right)}{\sqrt{a}}>0\forall a\) thỏa mãn ĐKXĐ
hay P>6
Part 1
1 into
2 which
3 happily
4 aspect
5 if
6 compulsory
Part 2
1c 2f 3b 4g 5a 6e
Part 3
1 opened
2 to be finished
3 repairing
4 driving
5 harmful
6 modernize
7 environmentalists
8 effectively
Part 4
1 disappointing -> disappointed
2 come -> came
Part 5
1 succeed although he tried
2 my father could speak
3 seen such an interesting
4 being made to protect
Part 6
1 forest
2 climate
3 in
4 fortunatelt
Part 7
1T 2F 3F 4F
Đặt \(log_2x=t\Rightarrow t\ge4\)
Phương trình trở thành: \(\sqrt{t^2-2t-3}=m\left(t-3\right)\)
\(\Leftrightarrow\sqrt{\left(t+1\right)\left(t-3\right)}=m\left(t-3\right)\)
\(\Leftrightarrow\sqrt{t+1}=m\sqrt{t-3}\)
\(\Leftrightarrow m=\sqrt{\dfrac{t+1}{t-3}}\)
Hàm \(f\left(t\right)=\sqrt{\dfrac{t+1}{t-3}}\) nghịch biến khi \(t\ge4\)
\(\lim\limits_{t\rightarrow+\infty}\sqrt{\dfrac{t+1}{t-3}}=1\) ; \(f\left(4\right)=\sqrt{5}\)
\(\Rightarrow1< f\left(t\right)\le\sqrt{5}\Rightarrow1< m\le\sqrt{5}\)
Đáp án D
a: Xét (O) có
ΔABC nội tiếp đường tròn
AB là đường kính
Do đó: ΔABC vuông tại C
(-172)+56+(-26)+72
= ( -172 + 72 ) + ( -26 + 56 )
= -100 + 30
= -70
(-172)+56+(-26)+72
=-172+56-26+72
=(-172+72)+(56-26)
=-100+30
=-70