4/3*6 + 4/6*9 + 4/9*12 + 4/12*15 = ?
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Gọi tổng trên là A
A = 3/4(3/3.6 + 3/6.9 + 3/9.12 + 3/12.15)
A = 3/4( 1 - 1/6 + 1/6 - 1/9 + 1/9 - 1/12 + 1/12 - 1/15)
A = 3/4(1 - 1/15)
A = 3/4 . 14/15
A = 7/10
Nếu có gì sai thì nói với mk nha
4/3x6 + 4/6x9 + 4/9x12 + 4/12x15
=4/3x(1/3-1/6+1/6 -1/9 + 1/9 - 1/12 +1/12 - 1/15)
=4/3 x (1/3-1/15)
=4/3 x 4/15
=16/45
chúc bạn làm bài tốt nhé
\(\frac{6}{5}-\frac{1}{4}+\frac{4}{5}-\frac{3}{4}\)
\(=\left(\frac{6}{5}+\frac{4}{5}\right)-\left(\frac{1}{4}+\frac{3}{4}\right)\)
\(=2-1\)
\(=1\)
\(\frac{7}{9}-\frac{5}{12}+\frac{2}{9}-\frac{7}{12}\)
\(=\left(\frac{7}{9}+\frac{2}{9}\right)-\left(\frac{5}{12}+\frac{7}{12}\right)\)
\(=1-1\)
\(=0\)
các câu sau tương tự
A=1
B=0
C=ÂM 8/15
D=0
E=2
F=3/2
H=2/3
LẦN SAU CHO KHÓ SÍU NHA LỚP 5 CŨNG LÀM ĐC
\(A=\frac{1}{1\cdot2}+\frac{2}{2\cdot4}+\frac{3}{4\cdot7}+\frac{4}{7\cdot11}+...+\frac{10}{46\cdot56}\)
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{46}-\frac{1}{56}\)
\(A=1-\frac{1}{56}\)
\(A=\frac{55}{56}\)
\(B=\frac{4}{3\cdot7}+\frac{4}{7\cdot11}+\frac{4}{11\cdot15}+...+\frac{4}{23\cdot27}\)
\(B=\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{15}+...+\frac{1}{23}-\frac{1}{27}\)
\(B=\frac{1}{3}-\frac{1}{27}\)
\(B=\frac{8}{27}\)
\(C=\frac{4}{3\cdot6}+\frac{4}{6\cdot9}+\frac{4}{9\cdot12}+...+\frac{4}{99\cdot102}\)
\(C=\frac{4}{3}\left(\frac{3}{3\cdot6}+\frac{3}{6\cdot9}+\frac{3}{9\cdot12}+...+\frac{3}{99\cdot102}\right)\)
\(C=\frac{4}{3}\left(\frac{1}{3}-\frac{1}{6}+\frac{1}{6}-\frac{1}{9}+\frac{1}{9}-\frac{1}{12}+...+\frac{1}{99}-\frac{1}{102}\right)\)
\(C=\frac{4}{3}\left(\frac{1}{3}-\frac{1}{102}\right)\)
\(C=\frac{4}{3}\cdot\frac{33}{102}\)
\(C=\frac{22}{51}\)
\(\frac{4}{3}\times6+\frac{4}{6}\times12+\frac{4}{12}\times15\)
\(=\frac{4}{3}\times6+\frac{2}{3}\times6\times2+\frac{1}{3}\times15\)
\(=\left(\frac{4}{3}+\frac{2}{3}\right)\times6\times2+5\)
\(=2\times6\times2+5\)
\(=24+5\)
\(=29\)