Câu 1: Thực hiện phép tính :
a) \(2.\left(\dfrac{-2}{3}\right)^2-\dfrac{7}{2}\)
b) 5 \(\dfrac{4}{13}.\dfrac{-3}{4}+3\dfrac{9}{13}.\left(-0,75\right)\)
c) \(\left(-1\right)^{2017}+\left|\dfrac{-1}{13}\right|+\sqrt{\dfrac{144}{169}}\)
Câu 2: Sắp xếp các số thực sau theo thứ tự giảm dần:
-3,21; 1; 0; \(\sqrt{7}\); \(\dfrac{33}{7}\); \(\sqrt{-13}\); \(\dfrac{1}{3}\)
Câu 3: Tìm x, biết:
a) \(\dfrac{3}{5}-x=25\)
b)...
Đọc tiếp
Câu 1: Thực hiện phép tính :
a) \(2.\left(\dfrac{-2}{3}\right)^2-\dfrac{7}{2}\)
b) 5 \(\dfrac{4}{13}.\dfrac{-3}{4}+3\dfrac{9}{13}.\left(-0,75\right)\)
c) \(\left(-1\right)^{2017}+\left|\dfrac{-1}{13}\right|+\sqrt{\dfrac{144}{169}}\)
Câu 2: Sắp xếp các số thực sau theo thứ tự giảm dần:
-3,21; 1; 0; \(\sqrt{7}\); \(\dfrac{33}{7}\); \(\sqrt{-13}\); \(\dfrac{1}{3}\)
Câu 3: Tìm x, biết:
a) \(\dfrac{3}{5}-x=25\)
b) \(\dfrac{2}{3}\left|x-1\right|+\dfrac{1}{4}=\dfrac{5}{3}\)
P/s: giúp mk nhanh nha mk đg cần gấp! thank you
Câu 1: Thực hiện phép tính :
a) \(2.\left(\dfrac{-2}{3}\right)^2-\dfrac{7}{2}=2.\dfrac{4}{9}-\dfrac{7}{2}\)
\(=\dfrac{8}{9}-\dfrac{7}{2}\)
\(=\dfrac{16}{18}-\dfrac{63}{18}=\dfrac{-47}{18}\)
\(b,5\dfrac{4}{13}.\dfrac{-3}{4}+3\dfrac{9}{13}.\left(-0,75\right)=\dfrac{69}{13}.\dfrac{-3}{4}+\dfrac{48}{13}.\dfrac{-3}{4}\)
\(=\left(\dfrac{69}{13}+\dfrac{48}{13}\right).\dfrac{-3}{4}\)
\(=\dfrac{117}{13}.\dfrac{-3}{4}\)
\(=9.\dfrac{-3}{4}=\dfrac{-27}{4}\)
\(c,\left(-1\right)^{2017}+\left|\dfrac{-1}{13}\right|+\sqrt{\dfrac{144}{169}}=-1+\dfrac{1}{13}+\dfrac{12}{13}\)
\(=-1+\dfrac{13}{13}\)
\(=-1+1=0\)
Câu 3: Tìm x, biết:
a)\(\dfrac{3}{5}-x=25\)
\(x=\dfrac{3}{5}-\dfrac{125}{5}\)
\(x=\dfrac{-122}{5}\)
b)\(\dfrac{2}{3}\left|x-1\right|+\dfrac{1}{4}=\dfrac{5}{3}\)
\(\dfrac{2}{3}\left|x-1\right|=\dfrac{20}{12}-\dfrac{3}{12}\)
\(\dfrac{2}{3}\left|x-1\right|=\dfrac{17}{12}\)
\(\left|x-1\right|=\dfrac{17}{12}:\dfrac{2}{3}\)
\(\left|x-1\right|=\dfrac{17}{12}.\dfrac{3}{2}\)
\(\left|x-1\right|=\dfrac{17}{8}\)
Ta có 2 TH: TH1:\(x-1=\dfrac{17}{8}\) TH2:\(x-1=\dfrac{-17}{8}\) \(x=\dfrac{17}{8}+1\) \(x=\dfrac{-17}{8}+1\) \(x=\dfrac{17}{8}+\dfrac{8}{8}=\dfrac{25}{8}\) \(x=\dfrac{-17}{8}+\dfrac{8}{8}=\dfrac{-9}{8}\) Vậy x∈\(\left\{\dfrac{25}{5};\dfrac{-9}{8}\right\}\)