Tìm X
a) ( X - 3)2 = ( X - 3)4
b) 3 × 2X+1 + 2X+2=40
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\(B=\frac{1+2+2^2+2^3+...+2^{2008}}{1-2^{2009}}\)
Đặt: \(A=1+2+2^2+2^3+....+2^{2008}\)
\(\Rightarrow2A=2+2^2+2^3+2^4+...+2^{2009}\)
\(\Rightarrow2A-A=\left(2+2^2+2^3+2^4+...+2^{2009}\right)-\left(1+2+2^2+2^3+....+2^{2008}\right)\)
\(\Rightarrow2^{2009}-1\)
\(\Rightarrow B=\frac{2^{2009}-1}{1-2^{2009}}\)
\(9\times\left(x-3\right)-3\times\left(1-x\right)=23\)
\(\Rightarrow9\times x-27-3+3\times x=23\)
\(\Rightarrow12\times x-30=23\)
\(\Rightarrow12\times x=53\)
\(\Rightarrow x=\frac{53}{12}\)
2x-51:17=5
2x-51 =5.17
2x-51 =85
2x =85+51
2x =136
x =136:2
x 68
k mik nha
Ta có: (X-3)2=(X-3)4
=>X-3)4-(X-3)2=0
=>(X-3)2.(X-3.X-3-1)=0
=>(X-3)2= 0 hoặc X-3.X-3-1=0
Suy ra x=3;4
b, 3.(2x+1)+2x+2
=3.2x+1+2x+1.2
=2x+1.(3+2)
=2x+1.5=40
=2x+1=40:5=8
=2x+1=23
=>x+1=3
=>x=3-1=2
=> là suy ra nha bạn
a) ( X - 3 ) 2 = ( X - 3 )4 <=> X - 3 =1
=> X = 1+3
=> X = 4
Chú thích <=> : khi và chỉ khi
=> : suy ra
b) Mình ko biết ______________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________-sorry-____________________________________________________________________________________________________________________________________-__________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________