Phân tích đa thức 5x3-20 thành nhân tử
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\(=5x\left(x^2-2xy+y^2\right)\)
\(=5x\left(x-y\right)^2\)
a) \(5x^3-10x^2+15x=5x\left(x^2-2x+3\right)\)
b) \(x^2-3x+2=x\left(x-2\right)-\left(x-2\right)=\left(x-2\right)\left(x-1\right)\)
\(a)(x-1)x+(x-1)y\)
\(=(x-1)(x+y)\)
\(b)5x^3+15xy\)
\(=5x(x^2+3y)\)
\(c)6xy^2-8x^2y\)
\(=2xy(3y-4x)\)
\(d)2x^3+4x^2-6x\)
\(=2x(x^2+2x-3)\)
\(e)5(x-3)-20(3-x)\)
\(=5(x-3)+20(x-3)\)
\(=(x-3)(5+20)\)
\(=25(x-3)\)
a: =(x-1)(x+y)
b: =5x(x^2+3y)
c: 6xy^2-8x^2y=2xy(3y-4x)
d: =2x(x^2+2x-3)
=2x(x+3)(x-1)
e: =25(x-3)
a) \(24x^2-4xy\)
\(=4x\left(6x-y\right)\)
b) \(5x^3-10x^2+5x-20xy^2\)
\(=5x\left(x^2-10x+5-20y^2\right)\)
a) 7x – 14 = 7(x - 2)
b) 5x3 - 10x2y +5xy2 = 5x(x2 - 2xy - y2) = 5x(x - y)2
c) 25 – x2= (x - 5)(x + 5)
a, \(7\left(x-2\right)\)
c, \(\left(5-x\right)\left(5+x\right)\)
\(a,=\left(x-y\right)\left(x+y\right)-\left(x+y\right)=\left(x+y\right)\left(x-y-1\right)\\ b,=\left(x+y\right)\left(x-5\right)\\ c,=5x^2\left(x-y\right)-10x\left(x-y\right)=5x\left(x-2y\right)\left(x-y\right)\\ d,=x^2-2xy=x\left(x-2y\right)\\ e,=\left(3x-2y\right)\left(9x^2+6xy+4y^2\right)\)
1.
$4x^2y+5x^3-x^2y^2=x^2(4y+5x-y^2)$
2.
$5x(x-1)-3y(1-x)=5x(x-1)+3y(x-1)=(x-1)(5x+3y)$
3.
$4x^2-25=(2x)^2-5^2=(2x-5)(2x+5)$
4.
$6x-9-x^2=-(x^2-6x+9)=-(x-3)^2$
5.
$x^2+4y^2+4xy=x^2+2.x.2y+(2y)^2=(x+2y)^2$
6.
$\frac{1}{64}-27x^3=(\frac{1}{4})^3-(3x)^3$
$=(\frac{1}{4}-3x)(\frac{1}{16}+\frac{3x}{4}+9x^2)$
7.
$x^3-6x^2+12x-8=x^3-3.x^2.2+3.x.2^2-2^3$
$=(x-2)^3$
8.
$x^2-x-y^2-y=(x^2-y^2)-(x+y)=(x-y)(x+y)-(x+y)$
$=(x+y)(x-y-1)$
9.
$5x-5y+ax-ay=5(x-y)+a(x-y)$
$=(x-y)(5+a)$
a/ \(=5x\left(x^2-2x+3\right)\)
b/ \(=\left(x^2-2x\right)-\left(x-2\right)=x\left(x-2\right)-\left(x-2\right)=\left(x-1\right)\left(x-2\right)\)
a) \(5x^3-10x^2+15x=5x\left(x^2-2x+3\right)\)
b) \(x^2-3x+2=x\left(x-1\right)-2\left(x-1\right)=\left(x-1\right)\left(x-2\right)\)
5x3 - 20
= 5.(x3 - 4)
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