1. √(9-4√5) - √(14+6√5)
2.(3√2+√10) +√(28-12√5)
3.√(4+2√3)× √(√3 - 1) 2
4. √(13-√160)-√(53+4√60)
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1: \(=\sqrt{5}-2-3-\sqrt{5}=-5\)
2: \(=3\sqrt{2}+\sqrt{10}+3\sqrt{2}-\sqrt{10}=6\sqrt{2}\)
3: \(=2\sqrt{2}-\sqrt{5}-4\sqrt{3}-\sqrt{5}=2\sqrt{2}-4\sqrt{3}-2\sqrt{5}\)
1: \(=\sqrt{5}-2-3-\sqrt{5}=-5\)
2: \(=3\sqrt{2}+\sqrt{10}+3\sqrt{2}-\sqrt{10}=6\sqrt{2}\)
3: \(=2\sqrt{2}-\sqrt{5}-4\sqrt{3}-\sqrt{5}=2\sqrt{2}-4\sqrt{3}-2\sqrt{5}\)
1+2+3+4+5+6+7+8+9+10=55
11+12+13+14+15+16+17+18+19+20=155
1+2+3+4+5+6+7+8+9+10+11+12+13+14 +15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30-50-53=362
Mk ko ghi lại đề nhé
1 = \(350-4.19+4.7\)
\(=350-4.\left(19+7\right)\)
\(=350+4.26\)
\(=350-104=246\)
2 Câu này mình vẫn chưa hiểu là bạn ghi 27 3/5 tức là 27.3/5 hay 27\(\dfrac{3}{5}\)nên mk bỏ qua nhé
3 Cái đoạn 1 1/3 y chang câu 2
4 \(=\dfrac{2}{3}+\dfrac{1}{3}.\dfrac{7}{18}.\dfrac{12}{7}\)
\(=\dfrac{2}{3}+\dfrac{7}{54}.\dfrac{12}{7}\)
\(=\dfrac{2}{3}+\dfrac{2}{9}=\dfrac{8}{9}\)
5 \(=2^2+10^2-\left[9.\left(112:8\right)-11\right].1\)
\(=4+100-\left(9.14-11\right)\)
\(=104-115\)\(=-11\)
6 Đoạn 6 3/5 y chang 2,3
7 \(=\left(\dfrac{2}{3}-1\right)+\left(\dfrac{2}{7}-\dfrac{3}{7}\right)-\left(\dfrac{1}{14}-\dfrac{3}{28}\right)\)
\(=\dfrac{-1}{3}+\dfrac{-1}{7}-\dfrac{-1}{28}\)
\(=\dfrac{-196}{588}+\dfrac{-84}{588}-\dfrac{-21}{588}\)\(=\dfrac{259}{588}\)
Làm tạm tạm thôi xl vì có 3 câu ko hiểu
mik cách ra nghĩa là ghi 27, 3 phần 5 (mấy câu khác cx zị)hog phải nhân nha
a) Ta có: \(\dfrac{-5}{7}\left(\dfrac{14}{5}-\dfrac{7}{10}\right):\left|-\dfrac{2}{3}\right|-\dfrac{3}{4}\left(\dfrac{8}{9}+\dfrac{16}{3}\right)+\dfrac{10}{3}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)\)
\(=\dfrac{-5}{7}\cdot\dfrac{3}{2}\cdot\dfrac{21}{10}-\dfrac{3}{4}\cdot\dfrac{56}{3}+\dfrac{10}{3}\cdot\dfrac{8}{15}\)
\(=\dfrac{-9}{4}-14+\dfrac{16}{9}\)
\(=\dfrac{-1621}{126}\)
b) Ta có: \(\dfrac{17}{-26}\cdot\left(\dfrac{1}{6}-\dfrac{5}{3}\right):\dfrac{17}{13}-\dfrac{20}{3}\left(\dfrac{2}{5}-\dfrac{1}{4}\right)+\dfrac{2}{3}\left(\dfrac{6}{5}-\dfrac{9}{2}\right)\)
\(=\dfrac{-17}{26}\cdot\dfrac{13}{17}\cdot\dfrac{-3}{2}-\dfrac{20}{3}\cdot\dfrac{3}{20}+\dfrac{2}{3}\cdot\dfrac{-33}{10}\)
\(=\dfrac{3}{4}-1-\dfrac{11}{5}\)
\(=-\dfrac{49}{20}\)
\(1+2+3+4+5+6+7+8+9+10=55\)
\(11+12+13+14+15+16+17+18+19+20=155\)
1. \(\sqrt{\left(9-4\sqrt{5}\right)}\) - \(\sqrt{\left(14+6\sqrt{5}\right)}\) = \(\sqrt{5+4-2\cdot2\sqrt{5}}\) - \(\sqrt{9+5+2\cdot3\sqrt{5}}\) = \(\sqrt{\left(2-\sqrt{5}\right)^2}\) - \(\sqrt{\left(3+\sqrt{5}\right)^2}\) = \(\sqrt{5}-2\) - \(3-\sqrt{5}\) = -5
1: \(=\sqrt{5}-2-3-\sqrt{5}=-5\)
2: \(=3\sqrt{2}+\sqrt{10}+3\sqrt{2}-\sqrt{10}=6\sqrt{2}\)
4: \(=2\sqrt{2}-\sqrt{5}-4\sqrt{3}-\sqrt{5}=2\sqrt{2}-4\sqrt{3}-2\sqrt{5}\)