Tìm x
a)(x^2-9) . (4^x-16)=0
b)5^x + 5^x+2=650
c)2^x+2-2^x=96
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\(1.x^2+11x=0\)
\(\Leftrightarrow x\left(x+11\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x+11=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=-11\end{cases}}\)
\(2.\left(x^2-1\right)\left(x^2-9\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(x-1\right)\left(x+9\right)\left(x-9\right)=0\)
chia thành 4 TH :
\(TH1:X-1=0\)
\(\Leftrightarrow x=1\)
\(TH2:x+1=0\)
\(\Leftrightarrow x=-1\)
\(TH3:X+9=0\)
\(\Leftrightarrow X=-9\)
\(TH4:x-9=0\)
\(\Leftrightarrow x=9\)
Kết luận ....
\(3.\left(\left|x+1\right|-5\right)\left(x^2-9\right)\)
\(\Leftrightarrow\left(\left|x+1\right|-5\right)\left(x-3\right)\left(x+3\right)=0\)
\(\Leftrightarrow\hept{\begin{cases}\left|x+1\right|-5=0\\x-3=0\\x+3=0\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}\left|x+1\right|=5\\x=3\\x=-3\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}x+1=+_-5\Leftrightarrow x+1=5,x+1=-5\Leftrightarrow x=4,x=-6\\x=3x\\x=-3\end{cases}}\)
kết luận x=.....
\(4.\left(3x-16\right)⋮\left(x+2\right)\)
\(\Leftrightarrow\left(3x+6\right)-22\)
\(\Leftrightarrow3\left(x+2\right)-22⋮\left(x+2\right)\)
Vì\(\left(x+2\right)⋮\left(x+2\right)\)
\(\Rightarrow\left(3x-16\right)⋮\left(x+2\right)\)
Kết luận x=.....
\(\text{a/96-3(x+1)=42}\)
\(3\left(x+1\right)=54\)
\(x+1=54:3\)
\(x+1=18\)
\(\Rightarrow x=17\)
\(\text{b/2.x-18=20}\)
\(2x=38\)
\(x=38:2\)
\(x=19\)
\(\text{c/134-5.(x+4)=34}\)
\(5\left(x+4\right)=100\)
\(x+4=100:5\)
\(x+4=20\)
\(\Rightarrow x=16\)
học tốt
a) 96-3(x+1)=42
3(x+1)=96-42
3(x+1)=54
x+1=54:3
x+1=18
x=18-1
Vậy x=17
b) 2x-18=20
2x=20+18
2x=38
x=38:2
x=19
Vậy x=19.
c) 134-5(x+4)=34
5(x+4)=134-34
5(x+4)=100
x+4=100:5
x+4=20
x=20-4
x=16
Vậy x=16.
a) 96-3(x+1)=42
3(x+1)=96-42
3(x+1)=54
x+1=54:3
x+1=18
x=18-1
x=17
Vậy x=17
b)2.x-18=20
2.x =20+18
2.x =38
x =38:2
x =19
Vậy x=19
c)134-5.(x+4)=34
5.(x+4)=134-34
5.(x+4)=100
x+4 =100:5
x+4 =20
x =20-4
x =16
Vậy x=16
\(\left(2.x-4\right).\left(x-1\right)=0\)
\(\Rightarrow\orbr{\begin{cases}2.x-4=0\\x-1=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=2\\x=1\end{cases}}\)
\(\orbr{\begin{cases}2X-4=0\\X-1=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}X=2\\X=1\end{cases}}\)
4.\(\left(2-x\right)\left(5-x\right)=0\)
\(\Leftrightarrow\hept{\begin{cases}2-x=0\\5-x=0\end{cases}\Leftrightarrow\hept{\begin{cases}x=2\\x=5\end{cases}}}\)
5.\(\left(4x-16\right)\left(8-2x\right)=0\)
\(\Leftrightarrow\hept{\begin{cases}4x-16=0\\8-2x=0\end{cases}\Leftrightarrow\hept{\begin{cases}4x=16\\-2x=-8\end{cases}\Leftrightarrow}\hept{\begin{cases}x=4\\x=4\end{cases}}}\)
Câu 4:
( 2- x ) . ( 5 - x ) = 0
=> 2 - x = 0 hoặc 5 - x = 0
=> x = 2 hoặc x = 5
Vậy x \(\in\){ 2 ; 5 }
Cậu 5:
( 4x - 16 ) . ( 8 - 2x ) = 0
=> 4x - 16 = 0 hoặc 8 - 2x = 0
=> 4x = 16 hoặc 2x = 8
=> x = 4 hoặc x = 4
Vậy x = 4
`a)4/5:3/x xx2/11=24/165`
`(4/5xx2/11)xx 3/x=8/55`
`8/55xx3/x=8/55`
`3/x=8/55:8/55`
`3/x=1`
`3:x=1`
`x=3:1`
`x=3`
____________________________________________
`b)4/3:x/5=5/13xx4/9`
`4/3:x/5=20/117`
`x/5=4/3:20/117`
`x/5=39/5`
`x=39`
A) 4/5:3/x X 2/11=24/165
\(\dfrac{4}{5}:\dfrac{3}{x}X\dfrac{2}{11}=\dfrac{24}{165}\)
\(\dfrac{3}{x}=\dfrac{24}{165}:\dfrac{4}{5}:\dfrac{2}{11}\)
\(\dfrac{3}{x}=1\)
\(\dfrac{3}{x}=\dfrac{3}{3}\)
=> x=3
B) \(\dfrac{4}{3}:\dfrac{x}{5}=\dfrac{5}{13}x\dfrac{4}{9}\)
\(\dfrac{4}{3}:\dfrac{x}{5}=\dfrac{20}{117}\)
\(\dfrac{x}{5}=\dfrac{4}{3}:\dfrac{20}{117}\)
\(\dfrac{x}{5}=\dfrac{39}{5}\)
=> x = 39
a) \(\left(x^2-9\right)\cdot\left(4^x-16\right)=0\)
\(\Rightarrow x^2-9=0\)hoặc \(4^x-16=0\)
\(x^2=9\) \(4^x=16\)
\(x^2=\left(\pm3\right)^2\) \(4^x=4^2\)
\(\Rightarrow x=\pm3\)hoặc \(x=2\)
b) \(5^x+5^{x+2}=650\)
\(\Rightarrow5^x+5^x\cdot25=650\)
\(\Rightarrow5^x\cdot\left(1+25\right)=650\)
\(\Rightarrow5^x\cdot26=650\)
\(\Rightarrow5^x=650\div26=25\)
\(\Rightarrow5^x=5^2\)
\(\Rightarrow x=2\)Vậy \(x=2\)
c) \(2^{x+2}-2^x=96\)
\(2^x\cdot4-2^x=96\)
\(2^x\cdot\left(4-1\right)=96\)
\(2^x\cdot3=96\)
\(2^x=96\div3=32\)
\(2^x=2^5\)Vậy \(x=5\)