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(x-1)(2x+1)+3(x-1)(x+2)(2x+1)
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12 tháng 10 2021
\(1,\\ a,=4\left(x-2\right)^2+y\left(x-2\right)=\left(4x-8+y\right)\left(x-2\right)\\ b,=3a^2\left(x-y\right)+ab\left(x-y\right)=a\left(3a+b\right)\left(x-y\right)\\ 2,\\ a,=\left(x-y\right)\left[x\left(x-y\right)^2-y-y^2\right]\\ =\left(x-y\right)\left(x^3-2x^2y+xy^2-y-y^2\right)\\ b,=2ax^2\left(x+3\right)+6a\left(x+3\right)\\ =2a\left(x^2+3\right)\left(x+3\right)\\ 3,\\ a,=xy\left(x-y\right)-3\left(x-y\right)=\left(xy-3\right)\left(x-y\right)\\ b,Sửa:3ax^2+3bx^2+ax+bx+5a+5b\\ =3x^2\left(a+b\right)+x\left(a+b\right)+5\left(a+b\right)\\ =\left(3x^2+x+5\right)\left(a+b\right)\\ 4,\\ A=\left(b+3\right)\left(a-b\right)\\ A=\left(1997+3\right)\left(2003-1997\right)=2000\cdot6=12000\\ 5,\\ a,\Leftrightarrow\left(x-2017\right)\left(8x-2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=2017\\x=\dfrac{1}{4}\end{matrix}\right.\\ b,\Leftrightarrow\left(x-1\right)\left(x^2-16\right)=0\Leftrightarrow\left[{}\begin{matrix}x=1\\x=4\\x=-4\end{matrix}\right.\)
24 tháng 9 2021
\(1,\\ 1,=15\left(x+y\right)\\ 2,=4\left(2x-3y\right)\\ 3,=x\left(y-1\right)\\ 4,=2x\left(2x-3\right)\\ 2,\\ 1,=\left(x+y\right)\left(2-5a\right)\\ 2,=\left(x-5\right)\left(a^2-3\right)\\ 3,=\left(a-b\right)\left(4x+6xy\right)=2x\left(2+3y\right)\left(a-b\right)\\ 4,=\left(x-1\right)\left(3x+5\right)\\ 3,\\ A=13\left(87+12+1\right)=13\cdot100=1300\\ B=\left(x-3\right)\left(2x+y\right)=\left(13-3\right)\left(26+4\right)=10\cdot30=300\\ 4,\\ 1,\Rightarrow\left(x-5\right)\left(x-2\right)=0\Rightarrow\left[{}\begin{matrix}x=2\\x=5\end{matrix}\right.\\ 2,\Rightarrow\left(x-7\right)\left(x+2\right)=0\Rightarrow\left[{}\begin{matrix}x=7\\x=-2\end{matrix}\right.\\ 3,\Rightarrow\left(3x-1\right)\left(x-4\right)=0\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=4\end{matrix}\right.\\ 4,\Rightarrow\left(2x+3\right)\left(2x-1\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=-\dfrac{3}{2}\\x=\dfrac{1}{2}\end{matrix}\right.\)
KB
1
4 tháng 10 2021
\(\left(x^2-x+2\right)\left(x-1\right)-x^2\left(x-1\right)^2+\left(2x+1\right)\left(x-1\right)^3\)
\(=\left(x-1\right)\left[x^2-x+2-x^2\left(x-1\right)+\left(2x+1\right)\left(x^2-2x+1\right)\right]\)
\(=\left(x-1\right)\left(x^2-x+2-x^3+x^2+2x^3-4x^2+2x+x^2-2x+1\right)\)
\(=\left(x-1\right)\left(x^3-x^2-x+3\right)\)
19 tháng 11 2021
\(=\left(x^2+3x\right)\left(x^2+3x+2\right)+1\\ =\left(x^2+3x\right)^2+2\left(x^2+3x\right)+1\\ =\left(x^2+3x+1\right)^2\)
NH
2
3 tháng 8 2015
Bài 1 :
\(x^2-6x+8=x^2-2x-4x+8=x\left(x-2\right)-4\left(x-2\right)=\left(x-4\right)\left(x-2\right)\)
Bài 2 :
\(x^8+x^7+1=x^8+x^7+x^6+x^5+x^4+x^3+x^2+x+1-x^6-x^5-x^4-x^3-x^2-x\)
\(=x^6\left(x^2+x+1\right)+x^3\left(x^2+x+1\right)+x^2+x+1-x^4\left(x^2+x+1\right)-x\left(x^2+x+1\right)\)
=\(\left(x^2+x+1\right)\left(x^6+x^3+1-x^4-x\right)\)
Tick đúng nha
HN
2
NV
Nguyễn Việt Lâm
Giáo viên
24 tháng 11 2021
\(x\left(x+1\right)\left(x+2\right)\left(x+3\right)+1\)
\(=\left(x^2+3x\right)\left(x^2+3x+2\right)+1\)
\(=\left(x^2+3x\right)^2+2\left(x^2+3x\right)+1\)
\(=\left(x^2+3x+1\right)^2\)
24 tháng 11 2021
x(x+1)(x+2)(x+3)+1
= [x(x+3)][(x+1)(x+2)]+1
=(x2+3x)(x2+3x+2)+1
Đặt x2+3x+1=y, ta có:
(y-1)(y+1)+1
=y2-1+1
=y2
Thay y=x2+3x+1, lại có:
(x2+3x+1)2
YH
1
30 tháng 7 2015
= (x4 + 2x2 + 1) + (2x4 + x2 + 2) - (x2 + x+1)2
= [(x2 + 1)2 - (x2 + x+1)2 ] + (2x4 + x2 + 2)
= (x2 + 1 + x2 + x + 1). (x2 + 1 - x2 - x- 1) + (2x4 + x2 + 2)
= (2x2 + x + 2) (-x) + (2x4 + x2 + 2) = -2x3 - x2 - 2x + 2x4 + x2 + 2 = -2x3 + 2x4 - 2x + 2
= -2x3. (1 - x) + 2.(1 - x) = (1- x). (-2x3 + 2) = 2.(1 - x)(1- x3) = 2. (1- x). (1- x) .(1 + x + x2) = 2.(1-x)2. (1 + x + x2)
NT
5
NA
3
2T
31 tháng 8 2019
\(A=\left(x-1\right)\left(x-2\right)\left(x-3\right)+\left(x-1\right)\left(x-2\right)-\left(x-1\right)\)
\(A=\left(x-1\right)\left(x^2-5x+6\right)+\left(x-1\right)\left(x-2\right)-\left(x-1\right)\)
\(A=\left(x-1\right)\left(x^2-5x+6\right)+\left(x-1\right)\left(x-2\right)-\left(x-1\right)\)\(A=\left(x-1\right)\left(x^2-5x+6+x-2\right)-\left(x-1\right)\)
\(A=\left(x-1\right)\left(x^2-4x+4\right)-\left(x-1\right)\)
\(A=\left(x-1\right)\left(x-2\right)^2-\left(x-1\right)\)
\(A=\left(x-1\right)\left[\left(x-2\right)^2-1\right]\)
\(A=\left(x-3\right)\left(x-1\right)^2\)
31 tháng 8 2019
link tham khảo
https://olm.vn/hoi-dap/detail/9212510579.html
hok tót
(x-1).(2x+1) + 3.(x-1).(x+2).(2x+1)
= (x-1).(2x+1).[1+3.(x+2)]
chúc bn học tốt
(x-1).(2x+1) + 3.(x-1).(x+2).(2x+1)
= (x-1).(2x+1).[1+3.(x+2)]
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